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maksim [4K]
3 years ago
12

Need help on 4,5,6 and 7 please ! I’m begging you

Mathematics
2 answers:
Nastasia [14]3 years ago
6 0

4.) 3/100 = 0.03

5.) 73% = 0.73

6.) 0.1 = 10%

7.) 254% = 2.54

I hope this is what you're looking for!

Alekssandra [29.7K]3 years ago
4 0

4. .03

5. .73

6. 1/10

7. .254

i hope im correct (: sorry if i am not


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X² + y² = 8
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Answer:

(2,2)~ \text{and}~ (-2,-2)

Step by step explanation:

x^2 +y^2 =8~~~~~~...(i)\\\\x-y=0~~~~~~~~~...(ii)\\\\\text{From (ii):}\\\\x-y = 0 \implies x = y\\\\\text{Substitute x = y  in eq (i):}\\\\~~~~~~y^2 +y^2 =8\\\\\implies 2y^2 = 8\\ \\\implies y^2 = \dfrac 82\\\\\implies y^2 = 4\\\\\implies y = \pm\sqrt 4\\\\\implies y = \pm 2\\\\\text{Substitute y = x  in equation (i):}\\ \\~~~~~~x^2 +x^2 = 8\\ \\\implies 2x^2 = 8\\\\\implies x^2 = \dfrac 82\\\\\implies x^2 = 4\\\\\implies x = \pm\sqrt 4\\\\\implies x = \pm2\\\\

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3 0
2 years ago
Solve and graph the inequality 4x – 10 < 18.
tiny-mole [99]

9514 1404 393

Answer:

  • The graph has an open circle at 7.
  • The arrow points left.

Step-by-step explanation:

Adding 10 and dividing by 4, we have ...

  4x < 28

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The comparison does not include the "equal to" case, so the circle at x=7 is open. Values of x less than 7 are in the solution set. Those values are found to the left of 7 on the number line.

  • The graph has an open circle at 7.
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5 0
3 years ago
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79,81,84,88,100,88,82 what is the mean of these numbers
Ivahew [28]

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Step-by-step explanation:

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Answer:

x^2+x+1

Step-by-step explanation:

Your welcomeeee

7 0
3 years ago
M&lt;2=4x+12 <br> Someone help
Katarina [22]
X=12. So this one says that it has 3 congruent sides so therefore it has to have 3 congruent angles. Here we have angle 2 and we have angle 60. Given the definition of triangle congruence, we can say that 60 is angle 2 and that the third angle is also 60 but it’s not relevant in this problem. So knowing that angle 2 is 4x+12 we solve for x by seeding that equal to 60 and then solving for x we get x=12. Hope this helps!!!!

8 0
2 years ago
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