Simultaneous equations 5x + 3y= 312x + y = 12 a. find for xb. find for y
2 answers:
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So to work this out we need to find the 4th root of each of those and pick the one that gives an integer.
A:![\sqrt[4]{1.6*10^1^1} = 632.455...](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B1.6%2A10%5E1%5E1%7D%20%3D%20632.455...)
This is a decimal therefore <em>not</em> an integer.
B:![\sqrt[4]{1.6*10^1^2} =1124.682...](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B1.6%2A10%5E1%5E2%7D%20%3D1124.682...)
Again a decimal, therefore <em>not </em>an integer.
C:![\sqrt[4]{1.6*10^1^3} =2000](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B1.6%2A10%5E1%5E3%7D%20%3D2000)
This is a whole number, so it <em>is </em>an integer.
D:![\sqrt[4]{1.6*10^1^4} =3556.558...](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B1.6%2A10%5E1%5E4%7D%20%3D3556.558...)
Decimal, therefore <em>not </em>an integer
E:![\sqrt[4]{1.6*10^1^5} =6324.555...](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B1.6%2A10%5E1%5E5%7D%20%3D6324.555...)
Again a decimal, <em>not</em> an integer.
The only one that gives an integer when put to the 4th root is C, therefore:
could be A^4, as the 4th root of it is an integer.
A:
B:
C:
D:
E:
The only one that gives an integer when put to the 4th root is C, therefore:
