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zhannawk [14.2K]

3 years ago

8

raina is riding on a bike that is 40 miles long. so far, she has ridden 28 miles of the course. What percentage of yhe course ha

s raina ridden so far?

1 answer:

notsponge [240]3 years ago

3 0

Raina has ridden 70% of the course so far.

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___________% of 60=15

Tasya [4]

Answer:

25%

Step-by-step explanation:

25% of 60 is 15 because 15 is 1/4 of 60 and 1/4 is 25%

4 0

3 years ago

Read 2 more answers

An Olympic hurdler was part of the way through her race when she fell. She got up and completed the final 353535 meters of her 1

guajiro [1.7K]

hurdler falled down before the 353535 steps of 100100100 race.

we need to find where she fell down

so we need subtract 353535 from 100100100

$100100100-353535=99746565$

she falled at 99746565 step before completing the race

5 0

3 years ago

X+y= -9<br> x+2y= -25<br><br> According to the system of equations above, what is the value of y?

Varvara68 [4.7K]

Try this option:
if x+y=-9 is I (one)
and x+2y=-25 is II (two), then
if II-I, then (x+2y)-(x+y)=-25+9 ⇔ y=-16.

6 0

3 years ago

Click on all the points that are solutions to y = x^2 - 9.

Oliga [24]

9514 1404 393

Answer:

B) (2, -5)

D) (3, 0)

Step-by-step explanation:

I find it convenient to let a graphing calculator plot the points and the graph.

The only two points on the graph of the curve are ...

(2, -5) and (3, 0)

3 0

3 years ago

A display of seed packets contains 24 zucchini seed packets and 28 other seed packets. What is the probability that a randomly s

Nonamiya [84]

Answer:

The probability is 6/13

Step-by-step explanation:

Number of zucchini seed packets = 24

Number of other seed packets = 28

Total number of packets = 24 + 28 = 52

Probability is given by

$P(E)=\frac{n(E)}{n(s)}\\\\n(E)=24,n(s)=52\\P(E)=\frac{24}{52}\\\\P(E)=\frac{6}{13}$

Hence, the required probability is 6/13

3 0

4 years ago