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77julia77 [94]
2 years ago
5

Make b the subject a= 1/4 b

Mathematics
2 answers:
11Alexandr11 [23.1K]2 years ago
4 0
4ab=1
b=1/4x
so answer is b=1/4x
dalvyx [7]2 years ago
3 0

<u>Answer</u>:

b =  4a

<u>Step-by-step explanation</u>:

a = \frac{b}{4}

b =  4a

<em>changing sides changes sign division to multiplication.</em>

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− 6/b ​−50=-49 what is b
Sedbober [7]

Answer:

-6

Step-by-step explanation:

-6/b-50=-49

step1;collect like terms

-6/b=-49+50

-6/b=1

step2;cross multiply

-6/b=1

-6=1b(1b can also be regarded as b)

b=-6

6 0
3 years ago
Need help! much appreciated
Volgvan

Answer:

C-D = <u>6</u>

A-B = <u>3.25</u>

D = <u>118</u>

Step-by-step explanation:

C-D = 6 because the line is the same as B-C

A-B = 3.25 because the line is the same as A-D

D = 118 because the angle of B is vertically opposite to D

7 0
3 years ago
Find the radius of convergence, r, of the series. ∞ xn 2n − 1 n = 1 r = 1 find the interval, i, of convergence of the series. (e
Bingel [31]
Assuming the series is

\displaystyle\sum_{n\ge1}\frac{x^n}{2n-1}

The series will converge if

\displaystyle\lim_{n\to\infty}\left|\frac{\frac{x^{n+1}}{2(n+1)-1}}{\frac{x^n}{2n-1}}\right|

We have

\displaystyle\lim_{n\to\infty}\left|\frac{\frac{x^{n+1}}{2(n+1)-1}}{\frac{x^n}{2n-1}}\right|=|x|\lim_{n\to\infty}\frac{\frac1{2n+1}}{\frac1{2n-1}}=|x|-\lim_{n\to\infty}\frac{2n-1}{2n+1}=|x|

So the series will certainly converge if -1, but we also need to check the endpoints of the interval.

If x=1, then the series is a scaled harmonic series, which we know diverges.

On the other hand, if x=-1, by the alternating series test we can show that the series converges, since

\left|\dfrac{(-1)^n}{2n-1}\right|=\dfrac1{2n-1}\to0

and is strictly decreasing.

So, the interval of convergence for the series is -1\le x.
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Answer:

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Step-by-step explanation:

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