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Julli [10]
3 years ago
11

Write an expression to describe each sequence.Then find the 10th term. -18,-36,-54,-72...

Mathematics
1 answer:
Eduardwww [97]3 years ago
7 0
The patter seems to be +18 therefore...
the 10th term is 180
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PLZ HELP!!!! The angle bisectors of the triangle ABC meet at point P. If PQ=8 and PA=17, what is the length of AR?
yan [13]

Answer:

15

Step-by-step explanation:

PQ=PR

AR=side2=√(hypotenuse)²-(side1)=√17²-8²=√225=15

8 0
3 years ago
Find the area of each regular polygon. Round your answer to the nearest tenth if necessary.
tatuchka [14]

*I am assuming that the hexagons in all questions are regular and the triangle in (24) is equilateral*

(21)

Area of a Regular Hexagon: \frac{3\sqrt{3}}{2}(side)^{2} = \frac{3\sqrt{3}}{2}*(\frac{20\sqrt{3} }{3} )^{2} =200\sqrt{3} square units

(22)

Similar to (21)

Area = 216\sqrt{3} square units

(23)

For this case, we will have to consider the relation between the side and inradius of the hexagon. Since, a hexagon is basically a combination of six equilateral triangles, the inradius of the hexagon is basically the altitude of one of the six equilateral triangles. The relation between altitude of an equilateral triangle and its side is given by:

altitude=\frac{\sqrt{3}}{2}*side

side = \frac{36}{\sqrt{3}}

Hence, area of the hexagon will be: 648\sqrt{3} square units

(24)

Given is the inradius of an equilateral triangle.

Inradius = \frac{\sqrt{3}}{6}*side

Substituting the value of inradius and calculating the length of the side of the equilateral triangle:

Side = 16 units

Area of equilateral triangle = \frac{\sqrt{3}}{4}*(side)^{2} = \frac{\sqrt{3}}{4}*256 = 64\sqrt{3} square units

4 0
3 years ago
Existing now, current ;real
mrs_skeptik [129]

Answer:

existing

Step-by-step explanation:

7 0
3 years ago
A pet store has C tanks of fish. Each tank has 38 fish. using C, write an expression for the total number of fish in the store.​
Arisa [49]

Answer:

total number of fish in the store

38 * C fish in store


3 0
3 years ago
What is the equation of a like that goes through the point 5,-2 and has a slope of. 6/5<br>​
castortr0y [4]

Answer:

y= 6/5x -8

Step-by-step explanation:

The slope-intercept form (basically the form for the equation of a line)

y=mx+b

m is the slope

x is the value you want to plug in, or the x term in a point (x, y)

we know so far,

y=6/5x + b

so to find the missing value let's plug in the x & y value from (5, -2) and use the given slope

-2 = 6/5(5) + b

6 / 5    x    5/1     or   6/5 times 5    is      30/5    or    6

so

-2 = 6 + b

subtract 6 from each side to isolate the b value or y-intercept ( the point on the graph that is on the y-axis)

-8 = b

6 0
3 years ago
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