we have
<u>The system of equations</u>
-------> equation 
-------> equation 
Substitute equation in equation
subtract 
both sides
Divide by 
both sides
the solution is the point 
therefore
the answer is
the solution to the system of equations is the point
7 + 3.(2 - 3x) = 67
3 brackets are distributed
7+6-9x = 67
13-9x = 67
-9x = 67
x = 67/-9
We need to find two numbers that multiply to 24 (last coefficient) and add to 10 (middle coefficient). Through trial and error, the two values are 6 and 4
6 + 4 = 10
6*4 = 24
So we can break up the 10ab into 6ab+4ab and then use factor by grouping
a^2 + 10ab + 24b^2
a^2 + 6ab + 4ab + 24b^2
(a^2+6ab) + (4ab+24b^2)
a(a+6b) + 4b(a+6b)
(a+4b)(a+6b)
Therefore, the original expression factors completely to (a+4b)(a+6b)
53 1/10 is the mixed number
