Answer:
W = 12
L = 16
Step-by-step explanation:
Givens
L = L
W = 1/2 L + 4
Perimeter = 56
Formula
2L + 2W = Perimeter
Solution
Sustitute
2L + 2(1/2L + 4) = 56
2L + L + 8 = 56
3L + 8 = 56
3L + 8 - 8 = 56 - 8
3L = 48
3L/3 = 48/3
L = 16
W = 1/2 L + 4
W = 8 + 4
W = 12
Check
2L + 2W = 56
2*16 + 2*12 = 56
32 + 24 = 56
56 = 56 and it checks.
Answer:
4r - 10s OR 4r + (-10s)
Step-by-step explanation:
There are no like terms so I can't do anything so the answer remains as 4r - 10s... UNLESS U WANT TO KEEP CHANGE CHANGE AND THEN YOUR FINAL ANSWER WILL BE 4r + (-10s)
Value=amount times cost per unit
paper=10 times 0.55
pencils=6 times 0.75
she bought 10 paper and 6 pencils
cost=10*0.55+6*0.75=$10.00 total
Answer:
Consider the proposition C=(p∧q∧¬r)∨(p∧¬q∧r)∨(¬p∧q∧r)
Step-by-step explanation:
This compound proposition C uses the outer disjunction (∨) then the proposition is true if and only if one of the three propositions (p∧q∧¬r),(p∧¬q∧r),(¬p∧q∧r) is true.
First, it is impossible that two or three of these propositions are simultaneously true. For example, if (p∧q∧¬r) and (p∧¬q∧r) are both true, then ¬r is true (from the first conjuntion) and r is true (from the second one), a contradiction. All the other possibilities can be discarded reasoning in the same way.
Since these propositions are mutually excluyent, C is true if and only if exactly one of the three propositions is true (and false otherwise). This can only happen if exactly two of p,q, and r are true and the other one is false. For example, (p∧q∧¬r) is true when p and q are true, and r is false.
