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sergij07 [2.7K]
3 years ago
14

Simplify all of these

Mathematics
2 answers:
kiruha [24]3 years ago
8 0

Answer:

1) option C, 4b + 4

2) option A, 7x

3) option C, 2a - 12

4) option D, 12x - 6

4vir4ik [10]3 years ago
7 0
4b
7x
5x
6x
their is ur answer
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A volleyball reaches its maximum height of 13 feet, 3 seconds after its served. Which of the following quadratics could model th
kykrilka [37]
If it reaches its maximum height a t=3 its velocity must be zero at t=3

dy/dx=0 at t=3

dA/dx=4x+12=24 at t=3 so this does not apply

dB/dx=-4x+12=0 at t=3 and B=13 at t=3 so B applies

dC/dx=-4x-12=-24 at t=3 so this does not apply

dD/dx=-4x-12=-24 at t=3 so this does not apply

dE/dx=-4x-12=-24 at t=3 so this does not apply

So only quadratic B: reaches a maximum height of 13 feet at 3 seconds.
3 0
3 years ago
Read 2 more answers
Please help me with this question
umka21 [38]

Answer:

3,500 people

Step-by-step explanation:

10% of 35,000 is the same as .10 × 35,000, or 3,500.

6 0
1 year ago
3. A rocket is launched vertically from the ground with an initial velocity of 64 ft / sec . ( a ) Write a quadratic function h
lys-0071 [83]

Answer:

See below.

Step-by-step explanation:

The rocket's  flight is controlled by its initial velocity and the acceleration due to gravity.

The equation of motion is h(t) = ut + 1.2 g t^2 where  u = initial velocity, g = acceleration due to gravity ( = - 32 ft s^-2) and t = the time.

(a) h(t) = 64t  - 1/2*32 t^2

h(t) = 64t - 16t^2.

(b) The graph will be a parabola which opens downwards  with a maximum at the point (2, 64) and x-intercepts at (0, 0) and (4, 0).

The y-axis is the height of the rocket and the x-axis  gives the time.

Maximum height = 64 feet, Time to maximum height = 2 seconds, and time in the air = 4 seconds.

6 0
3 years ago
Read 2 more answers
Please hurry
Lerok [7]

Answer:

-4

Step-by-step explanation:

 

7 0
3 years ago
What goes in the green box and what is 6 * 28 ​
Y_Kistochka [10]
6*28= 168
You put 168 in the green box
7 0
3 years ago
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