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kipiarov [429]
3 years ago
8

Solve by substitution3x - 3y = -6 z=-3x-3y+9 -4x+5y+z=8

Mathematics
1 answer:
Vanyuwa [196]3 years ago
4 0
1. Y= x+2
2. Y=Y
3. E^2 Al^3 ^2 anumbs
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Hey guys! Leave the answer in terms of pi :)
DaniilM [7]
A) if the diameter is 13 the radius is 6.5
(6.5 \times 6.5) \times \pi = 42.25\pi  \\  =  132.7323
b)if the diameter is 6 the radius will be 3
(3 \times 3) \times \pi = 9\pi  \\ = 28.27433
hope this helps
8 0
3 years ago
Find the inverse of the function f(x)= 2x - 4 and show explain each step used to find the inverse.
Alla [95]
your answer is
f^-1(×)=2+×/2
3 0
3 years ago
A student studying his classmates' cars' ages reports the 5-number summary as {1, 3, 4, 8, 20}. what is the iqr for his data?
timurjin [86]

IQR for the data {1, 3, 4, 8, 20} is 5.

Interquartile Range(IQR) for a data is defined as the difference between third quartile and first quartile.

denoted by  IQR=Q₃-Q₁              (Q₃ is third quartile and Q₁ is first quartile)

The five number summary of a data set is represented as

{minimum, first quartile , second quartile , third quartile , maximum}..…(1)

According to the question

{1, 3, 4, 8, 20}

On comparing it with equation   …(1)

minimum=1

Q₁ =3    , Q₂=4 , Q₃=8 , maximum =20

IQR=Q₃-Q₁

Substituting the values we get

IQR=8-3=5.

Therefore , Interquartile Range for the data {1, 3, 4, 8, 20} is 5.

Learn more about Inter Quartile Range here brainly.com/question/28037049

#SPJ4

3 0
1 year ago
Which of the following is a polynomial with roots: − square root of 5 , square root of 5 , and −3?
tresset_1 [31]
Roots: - √5 , √5, and - 3

=> these are factors of the polynomial: (x + √5), (x - √5), and (x + 3).

Multiply those three factors:

(x + √5) (x - √5) ( x + 3) = [x^2 - 5] ( x + 3 ) = x^2 + 3x^2 - 5x - 15

Therefore the polynomial x^2 + 3x^2 - 5x - 15 is a polynomial with the given roots.

Answer: option B. x^3 + 3x^2 - 5x - 15
4 0
4 years ago
What is 5-(-27-(-189+243x)) distributed
maw [93]
Sorry if this is wrong and it doesn't hep but I got 32
7 0
3 years ago
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