3 years ago

How to determine how many cubes fit inside a rectangular prism?

Mathematics

1 answer:

Sedbober [7]3 years ago

5 0

If you're talking about unit cubes, then the equation is

length*width*height

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G(x)=(5-x)/(2x-1) f(x)= (x+5)/(2x+1) what is g(f(x))

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$\bf \begin{cases}
g(x)=\cfrac{5-x}{2x-1}\\\\
f(x)=\cfrac{x+5}{2x+1}
\end{cases}\qquad g(~~f(x)~~)=\cfrac{5-f(x)}{2[f(x)]+1}
\\\\\\
g(~~f(x)~~)=\cfrac{5-\left(\frac{x+5}{2x+1} \right)}{2\left(\frac{x+5}{2x+1} \right)-1}\implies g(~~f(x)~~)=\cfrac{\frac{5(2x+1)-(x+5)}{2x+1}}{\frac{2x+10}{2x+1}-1}$

$\bf g(~~f(x)~~)=\cfrac{\frac{10x+5-x-5}{2x+1}}{\frac{2x+10-1(2x+1)}{2x+1}}\implies 
g(~~f(x)~~)=\cfrac{\frac{9x}{2x+1}}{\frac{2x+10-2x-1}{2x+1}}
\\\\\\
g(~~f(x)~~)=\cfrac{\frac{9x}{2x+1}}{\frac{9}{2x+1}}\implies g(~~f(x)~~)=\cfrac{\underline{9} x}{\underline{2x+1}}\cdot \cfrac{\underline{2x+1}}{\underline{9}}
\\\\\\
g(~~f(x)~~)=x$

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