Add together the time it takes to put on the four wheels and the hood.
2.054s +3.652s = 5.704s
multiple this answer by 42
5.706s times 42= 239.652s
answer number two is correct
Answer:
add all of them together (x and y’s) the divide the sum by the amt of numbers
Step-by-step explanation:
Answer:
Given the equation of line : 3x -2y = -18
Table values:
x y
0 9
2 12
4 15
6 18
-6 0
Now, plot these points (0,9), (2, 12), (4, 15) , (6, 18) and (-6, 0) on the co-ordinate planer, to graph the the line.
You can see the graph of the given equation as shown below.
Answer:
22.
R= -8, 15
S= -5, 9
T= -8,9
23.
J = 4, 4
K = 4, 3
L = 1, 1
M = 1, 4
Step-by-step explanation:
rotation of -90= y, -x
so R (-7, -5) = -5,7
S (-1, -2) = -2, 1
T (-1, -5) = -5, 1
now we translate 3 left (x-3) and 8 up (y+8)
R (-5, 7) = -8, 15
S (-2, 1) = -5, 9
T (-5, 1) = -8, 9
reflection of x-axis= x, -y
J (-4, 4) = -4, -4
K (-3, 4) = -3, -4
L (-1, 1) = -1, -1
M (-4, 1) = -4, -1
Then a 180° rotation is (-y, -x)
J (-4, -4) = 4, 4
K (-3, -4) = 4, 3
L (-1, -1) = 1, 1
M (-4, -1) = 1, 4
The probability of one head and one tail is 2/3.
<u>Step-by-step explanation</u>:
- The possibilities for flipping two fair coins are {T,T}, {H,H}, {H,T}, {T,H}
- Given the case that at least one coin lands on a head, So the total possibilities are {H,H}, {H,T}, {T,H} = 3 possibilities
- Required event is 1 head and 1 tail= {H,T}, {T,H} = 2 possibilities
To calculate the probability of one head and one tail,
Probability = required events / Total events
Probability = 2/3
