Solve by Factoring x^(2/3)-7x^(1/3)+10=0 x 2 3 − 7 x 1 3 + 10 = 0 x 2 3 - 7 x 1 3 + 10 = 0 Rewrite x 2 3 x 2 3 as ( x 1 3 ) 2 ( x 1 3 ) 2 . ( x 1 3 ) 2 − 7 x 1 3 + 10 = 0 ( x 1 3 ) 2 - 7 x 1 3 + 10 = 0 Let u = x 1 3 u = x 1 3 . Substitute u u for all occurrences of x 1 3 x 1 3 . u 2 − 7 u + 10 = 0
