1. You'll need to download this data, or copy it down by hand.
2. Rearrange the data from lowest to highest values.
3. You have 24 data points (an even number).
In this case, to find the 1st quadrant, take the left half (that is, the left 12) data points. Since 12 is an even number, you must find the average of the middle two of these 12 data points. Your result is the 1st quadrant.
To find the 3rd quadrant, find the middle two data points of the right-hand 12 data points. Average these two points. The result is the 3rd quadrant.
I’m having a hard time understanding your question
1/4 of a five gallon bucket is 1 1/4 gallons.
5-1 1/4=3 3/4 gallons left to fill.
Answer: 3 3/4 gallons
9514 1404 393
Answer:
Step-by-step explanation:
The extrema will be at the ends of the interval or at a critical point within the interval.
The derivative of the function is ...
f'(x) = 3x² -4x -4 = (x -2)(3x +2)
It is zero at x=-2/3 and at x=2. Only the latter critical point is in the interval. Since the leading coefficient of this cubic is positive, the right-most critical point is a local minimum. The coordinates of interest in this interval are ...
f(0) = 2
f(2) = ((2 -2)(2) -4)(2) +2 = -8 +2 = -6
f(3) = ((3 -2)(3) -4)(3) +2 = -3 +2 = -1
The absolute maximum on the interval is f(0) = 2.
The absolute minimum on the interval is f(2) = -6.
1, 0 , 8, and 2 would all lie on the y-axis