Answer:
I suppose we want to find the side length of the square.
We know that:
The area of the square is 49cm^2
The distance between one of the vertices of the square and the middle of the square is:
BE = 4.95cm
Now let's remember some things.
For a square of side length L, the area is:
A = L^2
and the diagonal length is:
D = √(2)*L
In this case, we know that half of the diagonal is equal to:
BE = 4.95 cm
Then the diagonal is:
D = 2*BE = 2*4.95cm = 9.9cm
And for the diagonal formula, we have:
D = 9.9cm = √(2)*L
Then the side length is:
L = 9.9cm/√(2) = 7cm
And if we check the area of this square, is:
A = L^2 = (7cm)^2 = 49cm^2
So it checks.
Then we can conclude that the sidelength of the square is 7cm, which means that:
AB = 7cm
BC = 7cm
CD = 7cm
DA = 7cm
Answer:
John and Mike are correct.
Step-by-step explanation:
Answer:
Your answer is B!
Step-by-step explanation:
Answer:
5/9
Step-by-step explanation:
If you draw the triangle out on a grid papar and draw a line across the 2 marker point from XY up of the YZ side, you will see that the line from that marker point across to the hypotenuse is actually 8. Then you find the area of the little triangle with legs 8 and 4 (since 6-2 is 4), and the area is 16. After that, find the total area of the big triangle, which is 12x6/2=36. Since we want to know the area of the quadrilateral at the bottom of the big triangle seperated by the 2 marker point, we subtract 16 from 36, which equals to 20. 20/36=5/9. And that is my final answer. I tested it and it is correct. I hope this helps.