3 years ago

Is the following equation quadratic? -6x^2+y=-6x^2+8x

Mathematics

1 answer:

anastassius [24]3 years ago

7 0

Answer:

yes it is quadratic

Step-by-step explanation:

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riadik2000 [5.3K]

Answer:

<h2> no, because the remainder is 126</h2>

Step-by-step explanation:

if x+3 is a factor, then -3 is a root of expression, and the remainder would be 0

calculating remainder:

$-3(-3)^3+6(-3)^2+6(-3)+9=-3\cdot(-27)+6\cdot9-18+9=\\\\=81+54-9=126$

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3 years ago

If f(x) = 3x2 1 and g(x) = 1 – x, what is the value of (f – g)(2)? 12 14 36 38

nikdorinn [45]

Answer:

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2 years ago

Yvette earns $3 for every 1/4 hour she works. what is her hourly rate of pay

Lunna [17]

Yvette's hourly rate of pay is $12.
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3 years ago

What single percentage change is equivalent to a 11% increase followed by a 15% increase?

AlekseyPX

Answer:

It's a total increase by 27,65%

Step-by-step explanation:

1,11 × 1,15 = 1,2765

1,2765 = +27,65%

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2 years ago

In ΔABC, if m ∠A = m∠C, m∠B = ß (where ß is an acute angle), and BC = x, which expression gives the length of b, the side opposi

chubhunter [2.5K]

Answer:

The length of b is $\sqrt{2x^2(1-cos\beta)}$ .

Step by step explanation:

Given information: In ΔABC, ∠A =∠C, ∠B = ß (where ß is an acute angle), and BC = x.

Since two angles are same therefore triangle ABC is an isosceles triangle and side AB and BC are congruent.

$AB=BC=x$

According to Law of cosine

$b^2=a^2+c^2-2ac\cos B$

$b^2=x^2+x^2-2(x)(x)\cos \beta$

$b^2=2x^2-2x^2\cos \beta$

$b^2=2x^2(1-\cos \beta)$

$\sqrt{2x^2(1-cos\beta)}$

Therefore the length of b is $\sqrt{2x^2(1-cos\beta)}$ .

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2 years ago