Answer:
C
Step-by-step explanation:
Solution:
1) Rewrite it in the form {a}^{2}-2ab+{b}^{2}, where a={d}^{2} and b=4
{({d}^{2})}^{2}-2({d}^{2})(4)+{4}^{2}
2) Use Square of Difference: {(a-b)}^{2}={a}^{2}-2ab+{b}^{2}
{({d}^{2}-4)}^{2}
3) Rewrite {d}^{2}-4 in the form {a}^{2}-{b}^{2} , where a=d and b=2
{({d}^{2}-{2}^{2})}^{2}
4) Use Difference of Squares: {a}^{2}-{b}^{2}=(a+b)(a-b)
{((d+2)(d-2))}^{2}
5) Use Multiplication Distributive Property: {(xy)}^{a}={x}^{a}{y}^{a}
{(d+2)}^{2}{(d-2)}^{2}
Done!
Answer:
$1,391.25
Step-by-step explanation:
Noon would be 12:00 PM which would be 4 hours ahead of 8:00 AM
We subtract $8,821 by $3,256 to get the amount earned between 8:00 AM and 12:00 PM
$8,821 - $3,256
= $5,565
The find the average taken in within those 4 hours we will have to divide the money earned by the hours
$5,565/4
= $1,391.25
6.7 10 squared positive 8
600 + 9.5x (less than or equal to) 900
600 fixed amount
9.5 is the variable changing amount and differs among number of students taken
