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2 years ago

Krystal’s poster project for reading class is 2 feet high and 1 1/2

Mathematics

2 answers:

muminat2 years ago

7 0

Took test thank you thank you I got it correct

Anna11 [10]2 years ago

5 0

Answer:

The area of Victoria's poster is twice the area of Krystal's poster.

How compare the areas of two similar posters

The two areas are shown in the image attached below. Each poster represents a rectangle and the ratio between the two areas (r_{A}rA ), no unit, is defined by the following formula:

r_{A} = \frac{w_{V}\cdot h_{V}}{w_{K}\cdot h_{K}}rA=wK⋅hKwV⋅hV (1)

Where:

w_{V}wV - Width of Victoria's poster, in feet.h_{V}hV - Height of Victoria's poster, in feet.w_{K}wK - Width of Krystal's poster, in feet.h_{K}hK - Height of Krystal's poster, in feet.

If we know that h_{V} = 4\,fthV=4ft , w_{V} = 1.5\,ftwV=1.5ft , h_{K} = 2\,fthK=2ft and w_{K} = 1.5\,ftwK=1.5ft , then the ratio between the two areas is:

r_{A} = \frac{(4)\cdot (1.5)}{(2)\cdot (1.5)}rA=(2)⋅(1.5)(4)⋅(1.5)

r_{A} = 2rA=2

The area of Victoria's poster is twice the area of Krystal's poster. \blacksquare■

To learn more on ratios, we kindly invite to check this verified question:

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For each day in New England, the probability that it is mostly cloudy is 0.10 . Cindi is planning to go leaf watching, and her f

kolbaska11 [484]

Answer:

0,37

Step-by-step explanation:

It will be easier if we noun the events.

A= Cindi's friend comes to England.

B= New England is mostly cloudly.

We are searching the probability of just A doesn´t happen or just A happens but not B.

The probability of A doesn´t happen is one minus the probability of A:

$=(A^{|} )=1-P(A)=1-0.7=0.3$

The events A and B are independent for this reason the probability than both occurs is the product of the probability of each event. It means:

$P(A \cap B)= P(A)P(B)=0.1*0.7=0.07$

The probability of A doesn´t happen or A and B happen is:

$P(A^{|} \cup (A \cap B))= P(A^{|} )+P (A \cap B)-P(A^{|} \cap A\cap B)=0.3+0.07-0=0.37$

Conclusively we have to rest the probability of A doesn´t happen and A and B happen, but A happens and doesn´t happen and the same time is impossible. For this reason, we have the same result.

$P(A^{|} \cup (A \cap B))-P(A^{|} \cap A\cap B)=0.37-0=0.38$