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VladimirAG [237]
2 years ago
14

Krystal’s poster project for reading class is 2 feet high and 1 1/2

Mathematics
2 answers:
muminat2 years ago
7 0
Took test thank you thank you I got it correct
Anna11 [10]2 years ago
5 0

Answer:

The area of Victoria's poster is twice the area of Krystal's poster.

How compare the areas of two similar posters

The two areas are shown in the image attached below. Each poster represents a rectangle and the ratio between the two areas (r_{A}rA ), no unit, is defined by the following formula:

r_{A} = \frac{w_{V}\cdot h_{V}}{w_{K}\cdot h_{K}}rA=wK⋅hKwV⋅hV     (1)

Where:

w_{V}wV - Width of Victoria's poster, in feet.h_{V}hV - Height of Victoria's poster, in feet.w_{K}wK - Width of Krystal's poster, in feet.h_{K}hK - Height of Krystal's poster, in feet.

If we know that h_{V} = 4\,fthV=4ft , w_{V} = 1.5\,ftwV=1.5ft , h_{K} = 2\,fthK=2ft and w_{K} = 1.5\,ftwK=1.5ft , then the ratio between the two areas is:

r_{A} = \frac{(4)\cdot (1.5)}{(2)\cdot (1.5)}rA=(2)⋅(1.5)(4)⋅(1.5)

r_{A} = 2rA=2

The area of Victoria's poster is twice the area of Krystal's poster. \blacksquare■

To learn more on ratios, we kindly invite to check this verified question:

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