1 Convert 12\frac{2}{3}12
3
2
to improper fraction. Use this rule: a \frac{b}{c}=\frac{ac+b}{c}a
c
b
=
c
ac+b
\frac{12\times 3+2}{3}\times 3\frac{1}{4}
3
12×3+2
×3
4
1
2 Simplify 12\times 312×3 to 3636
\frac{36+2}{3}\times 3\frac{1}{4}
3
36+2
×3
4
1
3 Simplify 36+236+2 to 3838
\frac{38}{3}\times 3\frac{1}{4}
3
38
×3
4
1
4 Convert 3\frac{1}{4}3
4
1
to improper fraction. Use this rule: a \frac{b}{c}=\frac{ac+b}{c}a
c
b
=
c
ac+b
\frac{38}{3}\times \frac{3\times 4+1}{4}
3
38
×
4
3×4+1
5 Simplify 3\times 43×4 to 1212
\frac{38}{3}\times \frac{12+1}{4}
3
38
×
4
12+1
6 Simplify 12+112+1 to 1313
\frac{38}{3}\times \frac{13}{4}
3
38
×
4
13
7 Use this rule: \frac{a}{b}\times \frac{c}{d}=\frac{ac}{bd}
b
a
×
d
c
=
bd
ac
\frac{38\times 13}{3\times 4}
3×4
38×13
8 Simplify 38\times 1338×13 to 494494
\frac{494}{3\times 4}
3×4
494
9 Simplify 3\times 43×4 to 1212
\frac{494}{12}
12
494
10 Simplify
\frac{247}{6}
6
247
11 Convert to mixed fraction
41\frac{1}{6}41
6
1
41 and 1/6
9514 1404 393
Answer:
- Keiko: 17
- Chang: 24
- Abdul: 68
Step-by-step explanation:
Let c represent the number of messages sent by Chang. Then Keiko sent (c-7) messages, and Abdul sent 4(c-7) messages. The total number sent was ...
c + (c -7) +4(c -7) = 109
6c -35 = 109 . . . . . . . . . . simplify
6c = 144 . . . . . . . . . . . add 35
c = 24 . . . . . . . . . . . divide by 6
c-7 = 17
4(c-7) = 68
Keiko sent 17, Chang sent 24, and Abdul sent 68 text messages.
Answer:
1/20
Step-by-step explanation:
if you do all kids there is 20. you have a 1 out of 20 people change so plz give brainest answer
Answer:
d = 5e
Step-by-step explanation:
Number of wagons = 5
Number of miles per wagon = e
Total number of mules = d
Hence, relationship between total mules d needed will be ;
Total mules = number of wagons * Numbe rof mules per wagon
d = 5e
