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GaryK [48]
3 years ago
15

Simplify:1/1-x^(b-a)+1/1-x^(a-b)​

Mathematics
2 answers:
Pachacha [2.7K]3 years ago
8 0

Answer:

<h3>1</h3>

Step-by-step explanation:

simplify:

1/1-x^(b-a)+1/1-x^(a-b)​

\frac{1}{1-x^{b-a}} + \frac{1}{1-x^{a-b}}\\= \frac{1-x^{a-b} + 1-x^{b-a}}{(1-x^{b-a})(1-x^{a-b})}\\=  \frac{1-x^{a-b} + 1-x^{b-a}}{(1-x^{b-a}-x^{a-b}+x^{b-a+a-b})}\\= \frac{1-x^{a-b} + 1-x^{b-a}}{(1-x^{b-a}-x^{a-b}+1)}\\= \frac{2-x^{a-b}-x^{b-a}}{2-x^{b-a}-x^{a-b}}\\= 1\\ \\

Hence the required answer is 1

ra1l [238]3 years ago
5 0

Answer:

<h3>hope it helps you have a great day keep smiling be happy stay safe </h3>

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​<br><br> f(1)=−6<br> f(2)=−4<br> f(n)=f(n−2)+f(n−1)<br> ​<br> f(n)=?
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The nth term of the sequence is 2n - 8

<h3>Equation of a function</h3>

The nth term of an arithmetic progression is expressed as;

Tn = a + (n - 1)d

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Given the following parameters

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Learn more on nth term of an AP here: brainly.com/question/19296260

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