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ikadub [295]
3 years ago
5

How would you find the area of this shape? ( rectangle and congruent triangle )

Mathematics
1 answer:
ale4655 [162]3 years ago
4 0
Once you know the height and width, multiply them to get the area of the square.<span> To </span>find<span> the perimeter of the square, add all four sides </span>together. <span>To </span>find the area of a triangle<span>, multiply </span>together<span> two of the sides not the hypotenuse and then multiply that figure by 1/2.</span>
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Write a polynomial function of least degree with the given zero. -1+ √ 2, √ 3
kirill115 [55]

Answer:

f(x) = x^{4} + 2x³ - 4x² - 6x + 3

Step-by-step explanation:

Note that radical zeros occur in conjugate pairs, thus

- 1 + \sqrt{2} is a zero then - 1 - \sqrt{2} is also a zero

\sqrt{3} is a zero then - \sqrt{3} is also a zero

Thus the corresponding factors are

(x - (- 1 + \sqrt{2}) ), (x - (- 1 - \sqrt{2}) ), (x - \sqrt{3}), (x - (- \sqrt{3})), that is

(x + 1 - \sqrt{2}), (x + 1 + \sqrt{2}), (x - \sqrt{3}), (x + \sqrt{3})

The polynomial is then the product of the roots

f(x) = (x + 1 - \sqrt{2})(x + 1 + \sqrt{2})(x - \sqrt{3})(x + \sqrt{3})

     = ((x + 1)² - (\sqrt{2})²)((x² - (\sqrt{3})²)

     = (x² + 2x + 1 - 2)(x² - 3)

     = (x² + 2x - 1)(x² - 3) ← distribute

     = x^{4} - 3x² + 2x³ - 6x - x² + 3

     = x^{4} + 2x³ - 4x² - 6x + 3

6 0
4 years ago
Use the GCF and the Distributive Property to find the sum.<br> 14+21
Whitepunk [10]

Answer:35

Step-by-step explanation:

Explanation in picture

The GCF is 7.

7 0
2 years ago
Simplify: (sin Θ − cos Θ)^2 + (sin Θ + cos Θ)^2
Ede4ka [16]
Hope this could help you

5 0
4 years ago
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Answer:

B. 8w = 96

Step-by-step explanation:

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3 years ago
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melamori03 [73]
6 x (-3)^13-1 = -3188646
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