If a triangle side lengths are 10 15 7 is it acute obtuse or right?

What fraction is represented by the tick mark labeled m

lianna [129]

M×
_
×

I brlive that is the answer

7 0

3 years ago

Hello, i am having a hard time solving this. If anyone can please explain how to solve it in order for me to solve future questi

lora16 [44]

Answer:

Step-by-step explanation:

7 0

1 year ago

Alex is making a pizza. The round pizza pan has a 16 inch diameter. What is the area of the pizza crust needed to fill the entir

Lubov Fominskaja [6]

Answer:

The area of the pizza crust is 200.96 inches²

Step-by-step explanation:

* Lets explain how to solve the problem

- The area of any circle is πr² , where r is the length of its radius

- The length of the diameter of any circle is twice the length of

its radius (diameter = 2 radius)

* Lets solve the problem

- Alex is making a pizza

- The round pizza pan has a 16 inch diameter

- To find the area of the pizza crust is needed to fill the entire pan,

calculate the area of the pan

∵ The diameter of the pan is 16 inches

∵ The radius of the pan = 1/2 diameter

∴ The radius of the pan = 1/2 (16) = 8 inches

∵ The area of the pan = πr²

∵ π = 3.14 and r = 8 inches

∴ The area pf the pan = 3.14 (8)² = 200.96 inches²

∵ The area of the pizza pan = the area of the pizza crust

∴ The area of the pizza crust is 200.96 inches²

7 0

2 years ago

WILL MARK BRAINLIST<br> Write all the factors of .32<br> Use commas to separate them

Fed [463]

Answer:

1, 2, 4, 8, 16, and 32

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

The area of a right triangle is sixty square centimetres. Its base is one centimetre less than twice its height. If the base and

NemiM [27]

Answer:

5. None of the above

Step-by-step explanation:

We have this information:

A = 60 cm2

b = 2*h - 1

Let's find out b and h:

The equation of the are of a triangle is A = (b*h)/2, if we replace it with our information, we have

$60 = ((2*h - 1) * h)/2\\ 120 = 2*h^2 - h\\ 0 = 2*h^2 - h - 120$

Let's find h with the quadratic formula:

$\fbox {Quadratic formula:} \frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$h = \frac{-(-1)\pm\sqrt{(-1)^2-4*2*(-120)}}{2*2} = \frac{1\pm\sqrt{961}}{4} = \frac{1\pm\ 31}{4}$

h = 8 or h = -7.5

But h represents the height of the triangle, so it has to be a positive number, that's h = 8.

If we replace this in the equation we had for b, we have that b = 2*8 - 1 = 15.

Now we can calculate the hypotenuse with the Pythagorean equation

$\fbox {Pythagorean equation:}$ <em>The square of the length of the hypotenuse (the side opposite the right angle) of a right triangle is equal to the sum of the squares of the two legs (the two sides that meet at a right angle). </em>

The base and the height are our legs. We will use "H" for the hypotenuse

$H^2 = b^2 + h^2 = 15^2 + 8^2 = 289\\ H = \sqrt {289} = 17$

H = 17

If we decrease the base and the height by 2 centimeters, we have

b' = 15 - 2 = 13 and h' = 8 - 2 = 6

With this, let's calculate the new hypotenuse:

$H'^2 = b'^2 + h'^2 = 13^2 + 6^2 = 205\\ H' = \sqrt {205} \approx 14.3$

$H' \approx 14.3$

So, the hypotenuse decreases $H - H' \approx 17 - 14.3 = 2.7$

3 0

2 years ago