To solve this, it might be easier to draw it out (see the picture below). I split it into two triangles and used trig functions to find the altitude. I used the big triangle to find theta, and the used theta to find the side of the altitude. *remember that sine= opposite/hypotenuse*
Answer:
t = 7 + 3i
Step-by-step explanation:
(t-7)^2 + 18 = 9
(t-7)^2 = 9 - 18
(t-7)^2 = -9
(t-7) = sqrt(-9) = |3| sqrt(-1)
t = 7 + 3i
Answer:

Step-by-step explanation:
see the attached figure to better understand the problem
we know that
m∠LOM+m∠MON=m∠LON ----> by angle addition postulate
we have
m∠LOM=2x°
m∠MON=x°
m∠LON=90° ----> is a right angle
substitute the values

solve for x


Solving for "K" , got it! :)
I'll make it easier to solve
(k)4+3-14=?
? = 0
4(k)-11 = 0
Take off the '0' and the addition symbol so we can add from 11 on your sides
4(k) - 11
+11 +11
---- ----
15k. 22
⬆ This would be your answer for k
4(k) = 11
÷4 ÷4
--- ----
1K ?
K = 11/4 (for fraction)
K = 2.75 (as a decimal)