Answer:
I think it is 123 for number 9 i can't see, the other problems
Step-by-step explanation:
If the total capacity of the basket is 24 to find 1/6 you divide 24 by 6 and get 4. 4 is equal to 1/6 of 24 which means Sandra can only bring 4 bananas.
Answer: a) x = 5 or -1 b) x = √3+2
c) x = -1/2 or -3/2
Step-by-step explanation:
a) (x − 2)² = 9
First step is to take the square root of both sides to eliminate the square
√ (x − 2)² = √9
x-2 = +-3
x = +3+2
x = 5 and;
x = -3+2
x = -1
x = 5 or -1
b) 3(x-2)² = 9
First we divide both sides by 3 to get;
(x-2)² = 9/3
(x-2)² = 3
Second step is to take the square root of both sides to eliminate the square
√(x-2)² = √3
x-2 = √3
x = √3+2
c) 6 = 24(x+1)²
Dividing both sides by 24, we have
6/24 = (x+1)²
1/4 = (x+1)²
Taking the square root of both sides we have
√1/4 = √(x+1)²
= +-1/2 = x+1
x = +1/2-1 = -1/2 and;
x = -1/2-1 = -3/2
x = -1/2 or -3/2
The idea of grouping is to get the terms in groups that allow you to factor out from each group something that becomes a factor in itself, leaving two factors behind that are alike. Like this: rearrange those terms so they are in this order:
(-70y^2 - 63xy) + (90x^3 + 100yx^2). Now out of the first set we are going to factor out a -7y, and out of the second set we are going to factor out a 10x^2. When we do this, this is what we get: -7y(10y + 9x) + 10x^2(9x + 10y). As you can see, what's inside both sets of parenthesis is the same, just in a different order. We can factor that out now, leaving (9x + 10y)(10x^2 - 7y). And that is factored by grouping.
9514 1404 393
Answer:
Step-by-step explanation:
You have to realize that the absolute value function will change the sign of its argument only if that argument is negative.
108. |x -7| = x -7 . . . . . true for x-7≥0
x ≥ 7 . . . . makes the statement true
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1a. When m < 9, the value 6m is less than 54, so 6m-54 < 0. That means the absolute value function changes the sign of its argument:
54 -6m . . . . . simplified form for m < 9
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1b. |y -x| = y -x . . . when y > x, the argument of the absolute value is positive
