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Marizza181 [45]
3 years ago
6

Plz help me out in that because i don’t what is the value of 5n+9+n

Mathematics
1 answer:
valentina_108 [34]3 years ago
4 0
No they’re not equivalent because for 3(2n+9) when you distribute the 3 you get 6n+27 & 5n+9+n equal to 6n+9 when you combine like terms (add the n’s).
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How many tons are in 512,000 ounces?
murzikaleks [220]

Answer:

16 Tons

Step-by-step explanation:

divide 512,00 by 32000

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A gym charges $45 per month and a $75 one-time starting fee. Which of these will show how much it costs to join the gym for one
Sauron [17]

Answer: 615

Step-by-step explanation: you take the 45 times 12 months plus the 75 for the one time fee.

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Oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were millio
JulijaS [17]

Answer:

The amount of oil was decreasing at 69300 barrels, yearly

Step-by-step explanation:

Given

Initial =1\ million

6\ years\ later = 500,000

Required

At what rate did oil decrease when 600000 barrels remain

To do this, we make use of the following notations

t = Time

A = Amount left in the well

So:

\frac{dA}{dt} = kA

Where k represents the constant of proportionality

\frac{dA}{dt} = kA

Multiply both sides by dt/A

\frac{dA}{dt} * \frac{dt}{A} = kA * \frac{dt}{A}

\frac{dA}{A}  = k\ dt

Integrate both sides

\int\ {\frac{dA}{A}  = \int\ {k\ dt}

ln\ A = kt + lnC

Make A, the subject

A = Ce^{kt}

t = 0\ when\ A =1\ million i.e. At initial

So, we have:

A = Ce^{kt}

1000000 = Ce^{k*0}

1000000 = Ce^{0}

1000000 = C*1

1000000 = C

C =1000000

Substitute C =1000000 in A = Ce^{kt}

A = 1000000e^{kt}

To solve for k;

6\ years\ later = 500,000

i.e.

t = 6\ A = 500000

So:

500000= 1000000e^{k*6}

Divide both sides by 1000000

0.5= e^{k*6}

Take natural logarithm (ln) of both sides

ln(0.5) = ln(e^{k*6})

ln(0.5) = k*6

Solve for k

k = \frac{ln(0.5)}{6}

k = \frac{-0.693}{6}

k = -0.1155

Recall that:

\frac{dA}{dt} = kA

Where

\frac{dA}{dt} = Rate

So, when

A = 600000

The rate is:

\frac{dA}{dt} = -0.1155 * 600000

\frac{dA}{dt} = -69300

<em>Hence, the amount of oil was decreasing at 69300 barrels, yearly</em>

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2 years ago
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Maurinko [17]

Answer:

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Given the function f, match the function g with a transformation of f.

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3 years ago
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