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3 years ago

How do you work out the Lowest Common Factor and Highest Common Factor between two numbers?

1 answer:

6 0

For example if you're doing 10 and 20 the common factors are what numbers are 10 5 2 1 because every single one of those numbers are abled to going into 10 and 20. The Hughes one is 10 and the lowest is 1.
To woke this out you do
1x10=10 1x20=20
2x5=10 2x10=20
But as 3 doesn't go into 10 or 20 you don't count it and even though 4 goes into 20 it doesn't going into 10 and so it can't be a common factor and vice versa.
The next one is 5 and the next one is ten as 5 times 2 is ten and 5 time 4 is 20 then 10 x 1 equals 10 and 10 times 2 equals 20. Hope this helps.
Then you just write which one is the highest and the lowest.

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3 years ago

tire and Jody's bedroom are shaped like rectangles Terrace bedroom is 9 ft long and 8 feet wide Jody's bedroom is 7 ft long and

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4 years ago

A box is being created out of a 15 inch by 10 inch sheet of metal. Equal-sized squares are cutout of the corners, then the sides

ivolga24 [154]

Answer:

Therefore the dimensions of the square should be 0.1528 inch by 0.1528 inch so, the box has largest volume.

Step-by-step explanation:

Given that,

A box is being created out of a 15 inches by 10 inches sheet of metal.

The length of the one side of the squares which are cut out of the each corners of the metal sheet be x.

The length of the metal box be = (15-2x) inches.

The width of the metal box be =(10-2x) inches

The height of the metal box be =x inches

Then, the volume of the metal box= length×width×height

=(15-2x)(10-2x)x cubic inches

=(150x-50x²+4x³) cubic inches

∴ V= 4x³-50x²+15x

Differentiating with respect to x

V'=12x²-100x+15

Again differentiating with respect to x

V''=24x-100

For maximum or minimum value, V'=0

12x²-100x+15=0

Apply quadratic formula $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ , here a=12, b= -100 and c=15

$x=\frac{-(-100)\pm\sqrt{(-100)^2-4.12.15}}{2.12}$

$\Rightarrow x=\frac{100\pm\sqrt{9280}}{2.12}$

$\Rightarrow x=0.1528,8.18$

For x= 8.18, The value of (15-2x) and (10-2x) will negative.

∴x=0.1528 .

Now, $V''|_{x=0.1528}=24(0.1528)-100$

∴At x=0.1528 inch, the volume of the metal box will be maximum.

Therefore the dimensions of the square should be 0.1528 inch by 0.1528 inch so, the box has largest volume.

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4 years ago