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Kazeer [188]
3 years ago
13

Please Help  Me With These QUESTIONS!!!!!!! I Give Thanks!!!!!!!

Mathematics
1 answer:
Bezzdna [24]3 years ago
8 0

1).  Total cost for a rental = $12 just to talk to them +  $8 per hour .

                     $44              =  12        + 8 (number of hours)

                       32              =                  8 (number of hours.
____________________

2).  333 = 6 x (number of students on each bus) + 9 mores students

       324 = 6 x (number of students on each bus) .
______________________________

3).  If all 3 numbers were the same number,
then each one would be  1/3 of 138.  That's 46 .

Take 1 away from one of the 46s and add it on to another 46 .
Their sum is still 138, but now you have 3 consecutive numbers.
________________________________

4).   $150 = cost of 6 books  +  $12 left over.

        $138 = cost of 6 books.
_________________________________

5).  If all three numbers were the same number,
then each of them would be  1/3 of 84.  That's  28.

Take 2 away from one of the 28s, and add it onto another one.  
Their sum is still 84, but now you have 3 consecutive even numbers.
_________________________________

6).  Keith has 45 cards today.
      This morning, before his dog ate any of them, he had 90.
       That was after he bought 6 new ones.
___________________________________

7).  Sandy has 14 comic books.
      Before she bought 6 new ones, she had 8 .
      That's the half she had left after she sold half of them.        
___________________________________

8).  Sally has $11 now.
       Before she earned $9 washing the car, she had $20 .
       That's the half she had left after she spent half at the movies.           
____________________________________

9).  Fred spent $31 for a soft drink and 7 candy bars.
      $3 of that was for the drink, so the 7 candy bars cost $28 .
_____________________________________

10). If all three numbers were the same number, then
each one would be  1/3 of 105.   That's  35 .
                  
Take 2 away from one of the 35s and
add it onto another one.

They still all add up to 105, but now you have
three consecutive odd numbers.

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Evaluate the indicated function for f(x)=x^2-7 and g(x) =x-2
enyata [817]

Answer:

f(g(x))=(x-2)^2 - 7

(x-2)(x-2) - 7

x^2-2x-2x+4-7

x^2-4x-3

g(f(x))=x^2-2-7

x^2-9

(x+3)(x-3)

Step-by-step explanation:

  1. to solve for f(x), replace x with the g(x).
  2. since we don't multiply a bracket with the negative or the positive signs to the
  3. exponent, you have to factor into two binomials.
  4. use the FOIL method to eliminate the brackets.
  5. add like-terms

  • to find g(x), replace x with the f(x).
  • add like-terms
  • since there's difference of square, factor them into two binomials
7 0
3 years ago
3(x² + 3x - 10)<br> Simply the expression
miv72 [106K]

Answer:

3x^{2}+9x-30

Step-by-step explanation:

Multiply the three into each number

3x^{2}+9x-30

5 0
3 years ago
Read 2 more answers
Solve Quadratic Equations by Factoring:
mr_godi [17]

Answer:

  1. x = 0 or 1
  2. x = ±i/4
  3. x = -5 (twice)

Step-by-step explanation:

Factoring is aided by having the equations in standard form. The first step in each case is to put the equations in that form. The zero product property tells you that a product is zero when a factor is zero. The solutions are the values of x that make the factors zero.

1. x^2 -x = 0

  x(x -1) = 0 . . . . . x = 0 or 1

__

2. 16x^2 +1 = 0

This is the "difference of squares" ...

  (4x)^2 - (i)^2 = 0

  (4x -i)(4x +i) = 0 . . . . . x = -i/4 or i/4 (zeros are complex)

__

3. x^2 +10x +25 = 0

  (x +5)(x +5) = 0 . . . . . x = -5 with multiplicity 2

5 0
2 years ago
HELPPPPP IM GIVING 50 POINTS FOR THIS !
azamat

4 cups = 1 quart

16 cups = 4 quarts

thx brainliest plz?

8 0
2 years ago
Read 2 more answers
Pls help being timed
Anna71 [15]

The inequality is a > 12, which means a is greater than 12. This means that we are looking for numbers that are greater than 12 to place into the solution set. Options A and B are incorrect because 10 and 11 are both numbers less than 12, respectively. Option D is also incorrect because the inequality specifies that the numbers in the solution must be greater than 12, not equal to it, so 12 is not a solution.

This leaves option C as the correct answer, because all of the solutions in the set (13, 14, and 15) are greater than 12.

Therefore, your answer is C.

Hope this helps!

5 0
2 years ago
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