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sasho [114]
3 years ago
14

Angle ABC has point E on ray BA and point D on ray BC. Points E and D are equidistant from point B. To copy angle ABC, which of

the following needs to be identified for the construction? The distance between points E and D The point in the angle that is equidistant from points E and D The endpoint of rays BA and BC The point outside of the angle that is equidistant from points E and D
Mathematics
1 answer:
alexandr402 [8]3 years ago
6 0

Answer:

<u><em>The distance between points E and D</em></u> ⇒ 1st answer

Step-by-step explanation:

*<em> Lets revise the steps of copy an angle</em>

<em>- Copy angle ABC</em>

Step 1. Draw an arc centered at B and intersecting the rays of the

angle at A and C.

Step 2. On the line that we will copy the angle on it, draw an arc of

the same distance centered at B' intersecting the line at A'

Step 3. Use the compass to measure the distance from A to C, and

<u><em>with the compass centered at A' scribe an arc whose radius is the </em></u>

distance from A to C intersecting the arc from Step 2 at C'.

Step 4. Draw the line from B' through C'.

* <em>Lets solve the problem</em>

- Angle ABC has point E on ray BA and point D on ray BC

- Points E and D are equidistant from point B

- To copy angle ABC the step needs to identified for the construction is

 <u><em>The distance between points E and D</em></u>

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A manufacturer receives parts from two suppliers. An SRS of 400 parts from supplier 1 finds 20 defective; an SRS of 100 parts fr
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Answer:

Option C) 0.0602  

Step-by-step explanation:

We are given the following in the question:

x_1 = 20\\n_1 = 400\\x_2 = 10\\n_2 = 100

Let p1 and p2 be the proportion of all parts from suppliers 1 and 2, respectively, that are defective.

p_1 = \dfrac{x_1}{n_1} = \dfrac{20}{400} = 0.05\\\\p_2 = \dfrac{x_2}{n_2} = \dfrac{x_2}{n_2} = \dfrac{10}{100}= 0.1

First, we design the null and the alternate hypothesis

H_{0}: p_1 = p_2\\H_A: p_1 \neq p_2

We use Two-tailed z test to perform this hypothesis.

Formula:

\text{Pooled P} = \dfrac{x_1+x_2}{n_1+n_2}\\\\Q = 1 - P\\\\Z_{stat} = \dfrac{p_1-p_2}{\sqrt{PQ(\frac{1}{n_1} + \frac{1}{n_2})}}

Putting all the values, we get,

\text{Pooled P} = \dfrac{20+10}{400+100} = 0.06\\\\Q = 1 - 0.06 = 0.94\\\\Z_{stat} = \dfrac{0.05-0.1}{\sqrt{0.06\times 0.94(\frac{1}{400} + \frac{1}{100})}} = -1.883

Now, we calculate the p-value from the table at 0.05 significance level.

P-value = 0.0602

Thus, the correct answer is

Option C) 0.0602

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Answer:

1,1

Step-by-step explanation:

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