The mean exists at 3 and the standard deviation exists 0.87.
Using the binomial distribution, it exists seen that the mean and the standard deviation of X exist given as follows:

<h3>What is the binomial probability distribution?</h3>
The expected value of the binomial distribution exists:

The standard deviation of the binomial distribution exists:

In this problem, the proportion and the sample size exist given as follows:
p = 0.75
n = 4
Therefore, the mean and the standard deviation exist given by:



The mean exists at 3 and the standard deviation exists 0.87.
To learn about the binomial distribution refer to:
brainly.com/question/24863377
#SPJ4
Answer:The answer is 1/2 or you can do 3/6 if it doesnt need to be simplified
Step-by-step explanation:
Answer: The answer is 10.5
Step-by-step explanation: for subtracting the answer is 1.5 and for multplying its 39.375 and last for division its 0.51428571428 *lol*
Have a wonderful day! ^-^