1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
nataly862011 [7]
2 years ago
11

I need help ASAP

Mathematics
2 answers:
Ipatiy [6.2K]2 years ago
7 0

Answer:

X + 6 ≤ 12

Step-by-step explanation:

3x + 6 ≤ 12

-6 -6

3x ≤ 6

/3 /3

x ≤ 2

dem82 [27]2 years ago
4 0

Answer:

The inequality is 6 + 3x ≤ 12 or x ≤ 2 .

Step-by-step explanation:

Given that $6 is for admission which is a fixed amount, $3 is charged per hour and must not spend more than $12. So the inequality will be :

Let x be the no. of hours,

6 + 3x ≤ 12

Solve :

6 + 3x ≤ 12

3x ≤ 12 - 6

3x ≤ 6

x ≤ 6 ÷ 3

x ≤ 2

You might be interested in
Estimate then record the product, 181×2
Sauron [17]
I estimated it is around or near 360
8 0
3 years ago
A bucket contains 4 red marbles, 10 blue marbles, 7 yellow marbles, and 5 green marbles.
Oliga [24]

Answer:

d.  15.3%

Step-by-step explanation:

There are a total of 4 + 10 + 7 + 5 = 26 marbles

P(pick a red) = 4/26 = 2/13 = .153 = 15.3%  

7 0
2 years ago
A rectangular swimming pool is bordered by a concrete patio. the width of the patio is the same on every side. the area of the s
andre [41]
Answer:

x = \frac{1}{4}\left(-(l + w) + \sqrt{l^2 + 6lw + w^2} \right)

where

l = length of the pool (w/o the patio)
w = width of the pool (w/o the patio)

Explanation: 

Let 

x = width of the patio
l = length of the pool (w/o the patio)
w = width of the pool (w/o the patio)

Since the pool is bordered by a complete patio, 

Length of the pool (with the patio) 
= (length of the pool (w/o the patio)) + 2*(width of the patio)
Length of the pool (with the patio) = l + 2x

Width of the pool (with the patio) 
= (width of the pool (w/o the patio)) + 2*(width of the patio)
Width of the pool (with the patio) = w + 2x

Note that

Area of the pool (w/o the patio)
=  (length of the pool (w/o the patio))(width of the pool (w/o the patio))
Area of the pool (w/o the patio) = lw

Area of the pool (with the patio)
= (length of the pool (w/o the patio))(width of the pool (w/o the patio))
= (l + 2x)(w + 2x)
= w(l + 2x) + 2x(l + 2x)
= lw + 2xw + 2xl + 4x²
Area of the pool (with the patio) = 4x² + 2x(l + w) + lw

Area of the patio
= (Area of the pool (with the patio)) - (Area of the pool (w/o the patio))
= (4x² + 2x(l + w) + lw) - lw
Area of the patio = 4x² + 2x(l + w)

Since the area of the patio is equal to the area of the surface of the pool, the area of the patio is equal to the area of the pool without the patio. In terms of the equation,

Area of the patio = Area of the pool (w/o the patio)
4x² + 2x(l + w) = lw
4x² + 2x(l + w) - lw = 0    (1)

Let 

a = numerical coefficient of x² = 4
b = numerical coefficient of x = 2(l + w)
c = constant term = -lw

Then using quadratic formula, the roots of the equation 4x² + 2x(l + w) - lw = 0 is given by

x = \frac{-b \pm  \sqrt{b^2 - 4ac}}{2a}
\\ = \frac{-2(l + w) \pm  \sqrt{(2(l + w))^2 - 4(4)(-lw)}}{2(4)} 
\\ = \frac{-2(l + w) \pm  \sqrt{(4(l + w)^2) + 16lw}}{8} 
\\ = \frac{-2(l + w) \pm  \sqrt{(4(l^2 + 2lw + w^2) + 4(4lw)}}{8}
\\ = \frac{-2(l + w) \pm  \sqrt{(4(l^2 + 2lw + w^2 + 4lw)}}{8}
\\ = \frac{-2(l + w) \pm  \sqrt{(4(l^2 + 6lw + w^2)}}{8}
= \frac{-2(l + w) \pm 2\sqrt{l^2 + 6lw + w^2}}{8} \\= \frac{2}{8}(-(l + w) \pm \sqrt{l^2 + 6lw + w^2}) \\x = \frac{1}{4}(-(l + w) \pm \sqrt{l^2 + 6lw + w^2}) \\\boxed{x = \frac{1}{4}\left(-(l + w) + \sqrt{l^2 + 6lw + w^2} \right) \text{ or }}
\\\boxed{x = -\frac{1}{4}\left((l + w) + \sqrt{l^2 + 6lw + w^2} \right)}


Since (l + w) + \sqrt{l^2 + 6lw + w^2} \ \textgreater \  0, -\frac{1}{4}\left((l + w) + \sqrt{l^2 + 6lw + w^2}\right) is negative. Since x represents the patio width, x cannot be negative. Hence, the patio width is given by 

\boxed{x = \frac{1}{4}\left(-(l + w) + \sqrt{l^2 + 6lw + w^2} \right)}




7 0
3 years ago
A volume a cylinder: V = 1\3 pi [tex] x^{2} h solve for h PLZ HELP!!!
DedPeter [7]

Volume   =   π • r² • height

Height = Volume / (PI * radius^2)

Source www.1728.com/diamform.htm


7 0
3 years ago
Sondra gets $75 a week, plus 10 percent of sales.
victus00 [196]
75 out of a hole lot
5 0
2 years ago
Other questions:
  • Find the reciprocal 8
    8·1 answer
  • 5 times what is 1590!?
    10·2 answers
  • With working steps :)​
    13·1 answer
  • 4.<br> Evaluate the expression.<br> 33 + 2 x 20 - 4^3 =
    12·2 answers
  • In the Accompanying diagram of circle O, chords AB and CD intersect at E, mAC=50 and mBD =150. Find m
    7·1 answer
  • Suppose that when your friend was born, your friend's parents deposited $7000 in an account paying 6.3% interest compounded quar
    10·1 answer
  • A cube has a volume of 125 cubic inches. What is the length of each edge?
    10·2 answers
  • (x^{2}y^{2}-\frac{1}-{2}xy+2y)(x-2y)
    11·1 answer
  • the results of a poll indicate that between 33% and 37% of the population of a town visit the library at least once a year. what
    12·1 answer
  • El número que falta en<br> (–15) × ____ × 8 × (–4) = –4320, es:
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!