


with that template in mind, let's see.
to the left by 3 units, C = +3
up by 1 unit, D = 1
![\bf g(x)=-x^2\\\\\\ g(x)=-1(1x+\stackrel{C}{0})^2+\stackrel{D}{0}\implies g(x)=-1(1x+3)^2+1 \\\\\\ g(x)=-(x+3)^2+1\impliedby f(x)\qquad \qquad f(-1.5)=-[(-1.5)+3]^2+1](https://tex.z-dn.net/?f=%5Cbf%20g%28x%29%3D-x%5E2%5C%5C%5C%5C%5C%5C%20g%28x%29%3D-1%281x%2B%5Cstackrel%7BC%7D%7B0%7D%29%5E2%2B%5Cstackrel%7BD%7D%7B0%7D%5Cimplies%20g%28x%29%3D-1%281x%2B3%29%5E2%2B1%0A%5C%5C%5C%5C%5C%5C%0Ag%28x%29%3D-%28x%2B3%29%5E2%2B1%5Cimpliedby%20f%28x%29%5Cqquad%20%5Cqquad%20f%28-1.5%29%3D-%5B%28-1.5%29%2B3%5D%5E2%2B1)
and surely you know how much that is.
Answer:219.96 yd²
Explanation:The area of the trapezoid can be calculated using the following rule:Area of trapezoid =

where:
b1 is the length of the first base
b2 is the length of the second base
h is the height
Now, in the given we have:b1 = 15.8 yd
b2 = 21.8 yd
h = 11.7 yd
Substitute with the givens in the above equation to get the area as follows:area =

Hope this helps :)
Answer:
y=3x-10
Step-by-step explanation:
For this, you would use the point slope formula, which is (y-y1)=m(x-x1). x1 and y1 are the coordinates from the ordered pair.
(y-y1)=m(x-x1)
(y-2)=3(x-4)
y-2=3x-12
y=3x-10
To check, you can plug the coordinates into the equation.
y=3x-10
(2)=3(4)-10
2=12-10
2=2
A = 34 x 2 = 68
b = 56/2 = 28
hope it helps