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4 years ago

What is the value of y in the equation 2 + y = −3?

2 answers:

8 0

I’ve done these questions before and i’ve gotten confused because I have trouble with nagative numbers but i’ve gotten better st it. It’s -5

11111nata11111 [884]4 years ago

8 0

Your right it is -5

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Gina sells 216 cakes in the ratio small :medium:large 5:7:12. The profit for one medium cake is twice the profit for one small c

Rus_ich [418]

To answer this question you need to first set up the small, medium, large number of cakes as a ratio with a total. From here you will create a new ratio of the correct number of small medium and large Cakes sold using the total 216. The factor would be to multiply by nine. -Step 1 in picture. After this you would read what the relationship is between a medium and a small and the large and the small profits are - Step 2 in picture. After this you would represents the total profit based on the number of small medium and large cakes that were sold. Making this equal to L648.45. To find the profit for one small, you would then divide 648.45 by the 495 you got when you simplify the expression. The answer is L1.31.

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3 years ago

Read 2 more answers

How would u write Subtract 2 from 5 times d

julsineya [31]

Answer:

5D-2

Step-by-step explanation:

5 times d = 5d. subtract 2 is after the 5d

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3 years ago

Which of the following is a regular quadrilateral

irga5000 [103]

Answer:

(B) square

Step-by-step explanation:

Square (regular quadrilateral): all four sides are of equal length (equilateral), and all four angles are right angles.

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3 years ago

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Kelly buys a shirt for $14 dollars and pays the store clerk $20 how much change will kelly get back

Ilia_Sergeevich [38]

Answer:

Step-by-step explanation:

6 maybe

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3 years ago

Given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle

Anastasy [175]

Answer:

Part 1) False

Part 2) False

Step-by-step explanation:

we know that

The equation of the circle in standard form is equal to

$(x-h)^{2} +(y-k)^{2}=r^{2}$

where

(h,k) is the center and r is the radius

In this problem the distance between the center and a point on the circle is equal to the radius

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Part 1) given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x+3)^{2} +(y-4)^{2}=r^{2}$

Find the distance (radius) between the center (-3,4) and (-6,2)

substitute in the formula of distance

$r=\sqrt{(2-4)^{2}+(-6+3)^{2}}$

$r=\sqrt{(-2)^{2}+(-3)^{2}}$

$r=\sqrt{13}\ units$

The equation of the circle is equal to

$(x+3)^{2} +(y-4)^{2}=(\sqrt{13}){2}$

$(x+3)^{2} +(y-4)^{2}=13$

Verify if the point (10,4) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=10,y=4

substitute

$(10+3)^{2} +(4-4)^{2}=13$

$(13)^{2} +(0)^{2}=13$

$169=13$ -----> is not true

therefore

The point is not on the circle

The statement is false

Part 2) given the center of the circle (1,3) and a point on the circle (2,6), (11,5) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x-1)^{2} +(y-3)^{2}=r^{2}$

Find the distance (radius) between the center (1,3) and (2,6)

substitute in the formula of distance

$r=\sqrt{(6-3)^{2}+(2-1)^{2}}$

$r=\sqrt{(3)^{2}+(1)^{2}}$

$r=\sqrt{10}\ units$

The equation of the circle is equal to

$(x-1)^{2} +(y-3)^{2}=(\sqrt{10}){2}$

$(x-1)^{2} +(y-3)^{2}=10$

Verify if the point (11,5) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=11,y=5

substitute

$(11-1)^{2} +(5-3)^{2}=10$

$(10)^{2} +(2)^{2}=10$

$104=10$ -----> is not true

therefore

The point is not on the circle

The statement is false

7 0

4 years ago