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3 years ago

What is the value of y in the equation 2 + y = −3?

2 answers:

8 0

I’ve done these questions before and i’ve gotten confused because I have trouble with nagative numbers but i’ve gotten better st it. It’s -5

11111nata11111 [884]3 years ago

8 0

Your right it is -5

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How do you make a function

dmitriy555 [2]

This site will tell you how https://sciencing.com/write-functions-math-8315770.html
I’m not very good at explaining it sorry

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3 years ago

What are the zeros of f(x) = (x − 5)(x − 4)(x − 2)?

Dominik [7]

Answer:

x=5 , x=4, x=2

i got this answer by setting the x-5=0 then solve for x. same for each x-5, x-4, x-2.

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3 years ago

Read 2 more answers

Monthly payments are usually less with this option

Charra [1.4K]

What do you mean about that?

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3 years ago

The probability density function of the time you arrive at a terminal (in minutes after 8:00 A.M.) is f(x) = 0.1 exp(−0.1x) for

Blababa [14]

$f_X(x)=\begin{cases}0.1e^{-0.1x}&\text{for }x>0\\0&\text{otherwise}\end{cases}$

a. 9:00 AM is the 60 minute mark:

$f_X(60)=0.1e^{-0.1\cdot60}\approx0.000248$

b. 8:15 and 8:30 AM are the 15 and 30 minute marks, respectively. The probability of arriving at some point between them is

$\displaystyle\int_{15}^{30}f_X(x)\,\mathrm dx\approx0.173$

c. The probability of arriving on any given day before 8:40 AM (the 40 minute mark) is

$\displaystyle\int_0^{40}f_X(x)\,\mathrm dx\approx0.982$

The probability of doing so for at least 2 of 5 days is

$\displaystyle\sum_{n=2}^5\binom5n(0.982)^n(1-0.982)^{5-n}\approx1$

i.e. you're virtually guaranteed to arrive within the first 40 minutes at least twice.

d. Integrate the PDF to obtain the CDF:

$F_X(x)=\displaystyle\int_{-\infty}^xf_X(t)\,\mathrm dt=\begin{cases}0&\text{for }x$

Then the desired probability is

$F_X(30)-F_X(15)\approx0.950-0.777=0.173$

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3 years ago

Fine the class width

WITCHER [35]

Answer:

class width is 5

Step-by-step explanation:

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3 years ago