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Solnce55 [7]
3 years ago
5

What is the value of y in the equation 2 + y = −3?

Mathematics
2 answers:
Ket [755]3 years ago
8 0
I’ve done these questions before and i’ve gotten confused because I have trouble with nagative numbers but i’ve gotten better st it. It’s -5
11111nata11111 [884]3 years ago
8 0
Your right it is -5                           
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Find the area ratio of a cube with volume 125 m to a cube with volume 64 m.
Viefleur [7K]
V=s^3
SA=6s^2
so

125=v
125=s^3
cube root both sides
5=s
A=6(5)^2=6(25)=150 m^2


64=v
64=s^3
cube root both sides
4=s

A=6(4)^2=6(16)=96 m^2

ratio is

150:96=25:16
5 0
3 years ago
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The given figure is a regular hexagon with side length 12 and radius 10. Find its area.
Strike441 [17]

Answer:

if i was to guess it would be 96 or 120 this one got me stumped also

Step-by-step explanation:

3 0
3 years ago
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Examine this algebraic expression:
elena-14-01-66 [18.8K]

Answer:

the variables are 4x and y the coefficients are 12 and the constant is 1/2

5 0
3 years ago
A random sample of 10 parking meters in a resort community showed the following incomes for a day. Assume the incomes are normal
GenaCL600 [577]

Answer:

A 95% confidence interval for the true mean is [$3.39, $6.01].

Step-by-step explanation:

We are given that a random sample of 10 parking meters in a resort community showed the following incomes for a day;

Incomes (X): $3.60, $4.50, $2.80, $6.30, $2.60, $5.20, $6.75, $4.25, $8.00, $3.00.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                         P.Q.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean income = \frac{\sum X}{n} = $4.70

            s = sample standard deviation = \sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }  = $1.83

            n = sample of parking meters = 10

            \mu = population mean

<em>Here for constructing a 95% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.</em>

<u>So, 95% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-2.262 < t_9 < 2.262) = 0.95  {As the critical value of t at 9 degrees of

                                            freedom are -2.262 & 2.262 with P = 2.5%}  

P(-2.262 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.262) = 0.95

P( -2.262 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu < 2.262 \times {\frac{s}{\sqrt{n} } } ) = 0.95

P( \bar X-2.262 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.262 \times {\frac{s}{\sqrt{n} } } ) = 0.95

<u>95% confidence interval for</u> \mu = [ \bar X-2.262 \times {\frac{s}{\sqrt{n} } } , \bar X+2.262 \times {\frac{s}{\sqrt{n} } } ]

                                         = [ 4.70-2.262 \times {\frac{1.83}{\sqrt{10} } } , 4.70+ 2.262 \times {\frac{1.83}{\sqrt{10} } } ]

                                         = [$3.39, $6.01]

Therefore, a 95% confidence interval for the true mean is [$3.39, $6.01].

The interpretation of the above result is that we are 95% confident that the true mean will lie between incomes of $3.39 and $6.01.

Also, the margin of error  =  2.262 \times {\frac{s}{\sqrt{n} } }

                                          =  2.262 \times {\frac{1.83}{\sqrt{10} } }  = <u>1.31</u>

4 0
3 years ago
Can anyone identify the two variables
valentina_108 [34]
The two variables are time (x) and distance (y)

And the answer is they will meet after 1 mile

The function of the aunt and uncle is y=25x+5

The function of yourself is y2=30x

Since you want to know when you’ll meet, you just resolve y=y2 or 25x+5=30x

Wich will be x=1 so 1 mile
8 0
3 years ago
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