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11Alexandr11 [23.1K]
4 years ago
13

The point StartRoot x EndRoot is plotted on the number line. A number line going from 9.8 to 10.7. StartRoot x EndRoot is plotte

d slightly to the left of 10.2. What whole number best approximates the value of x
Mathematics
2 answers:
FromTheMoon [43]4 years ago
7 0

Answer:

it's not 100 or 102, just took the test and got them both wrong.

Step-by-step explanation:

.

DENIUS [597]4 years ago
6 0

Answer:

The Awnser is 104

Step-by-step explanation:

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What is the value of f?
laiz [17]

Answer:

f(1/2) = -2

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Function Notation

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = 8x - 6

f(1/2) is x = 1/2

<u>Step 2: Evaluate</u>

  1. Substitute in <em>x</em>:                    f(1/2) = 8(1/2) - 6
  2. Multiply:                               f(1/2) = 4 - 6
  3. Subtract:                              f(1/2) = -2
5 0
3 years ago
Which expression is equivalent to...? Screenshots attached. Please help! Thank you.
Studentka2010 [4]

Answer:

4x^{3} y^{2} (\sqrt[3]{4 x y})

Step-by-step explanation:

Another complex expression, let's simplify it step by step...

We'll start by re-writing 256 as 4^4

\sqrt[3]{256 x^{10} y^{7} } = \sqrt[3]{4^{4} x^{10} y^{7} }

Then we'll extract the 4 from the cubic root.  We will then subtract 3 from the exponent (4) to get to a simple 4 inside, and a 4 outside.

\sqrt[3]{4^{4} x^{10} y^{7} } = 4 \sqrt[3]{4 x^{10} y^{7} }

Now, we have x^10, so if we divide the exponent by the root factor, we get 10/3 = 3 1/3, which means we will extract x^9 that will become x^3 outside and x will remain inside.

4 \sqrt[3]{4 x^{10} y^{7} } = 4x^{3} \sqrt[3]{4 x y^{7} }

For the y's we have y^7 inside the cubic root, that means the true exponent is y^(7/3)... so we can extract y^2 and 1 y will remain inside.

4x^{3} \sqrt[3]{4 x y^{7} } = 4x^{3} y^{2} \sqrt[3]{4 x y}

The answer is then:

4x^{3} y^{2} \sqrt[3]{4 x y} = 4x^{3} y^{2} (\sqrt[3]{4 x y})

4 0
3 years ago
Which ordered pair is a solution of the equation?<br> 7x-2y=-57x−2y=−5
Yuri [45]

Answer:

what ordered pairs?

Step-by-step explanation:

6 0
3 years ago
Put these decimals in order starting with the smallest.
iVinArrow [24]

Answer:

8.008

8.018

8.088

8.808

8.88

<em><u>If this helped, please consider picking this answer as the Brainliest Answer. Thank you!</u></em>

3 0
3 years ago
Read 2 more answers
HELP ME THIS IS DUE RN. ILL give 50 points and brainiest.
Maru [420]

Answer:

y = 8x + 21

Step-by-step explanation:

3 0
3 years ago
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