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gogolik [260]
3 years ago
15

The proportion of students who own a cell phone on college campuses across the country has increased tremendously over the past

few years. It is estimated that approximately 90% of students now own a cell phone. Fifteen students are to be selected at random from a large university. Assume that the proportion of students who own a cell phone at this university is the same as nationwide. Let X = the number of students in the sample of 15 who own a cell phone.
1. What is the appropriate distribution forX? **N = Normal, B = Binomial?
A. X is M(15, 0.9).
B, X is B(15, 09).
C. Xis B(15, 13.5).
D. Xis N(13,5, 1.16).
2. On average, how many students will own a cell phone in a simple random sample of 15 students?
a. 9.
b. 13
c. 13.5.
d. 14 17.
3. What is the standard deviation of the number of students who own a cell phone in a simple random sample of 15 students?
a. 0.077.
b. 0.09.
c. 1.16.
d. 1.35.
4. What is the probability that all students in a simple random sample of 15 students own a cell phone?
a. 0.
b. 0.1.
c. 0.206.
d. 0.9.

Mathematics
1 answer:
galina1969 [7]3 years ago
7 0

Complete Question

The complete question is shown on the uploaded image  

Answer:

1 ) The correct option B

2) The correct option is  C

3)  The correct option is  C

4)  The correct option is  C

Step-by-step explanation:

From the question we are told that

   The proportion that own a cell phone  is  p = 0.90

    The  sample  size is  n =  15

Generally the appropriate distribution for X is mathematically  represented as

      X  \ is  \ B( n , p )

So  

       X  \ is  \ B( 15 , 0.90 )

Generally the number students that  own a cell phone in a simple random sample of 15 students is mathematically represented as

              \mu  =  n  *  p

              \mu  =  15 *  0.90

              \mu  =   13.5

Generally the standard deviation of the number of students who own a cell phone in a simple random sample of 15 students is mathematically represented as

                \sigma  =  \sqrt{ n *  p *  q }

Where  q is mathematically evaluated as

          q =  1- p

           q =  1- 0.90

           q =  0.10

            \sigma  =  \sqrt{ 15 *  0.90 *  0.10 }

            \sigma  = 1.16

Generally the probability that all students in a simple random sample of 15 students own a cell phone is mathematically represented as

   P(X =  15) =  \left 15} \atop {}} \right.C_{15} *  p^{15} *  q^{15 - 15}    

     P(X =  15) =  \left 15} \atop {}} \right.C_{15} *  (0.90)^{15} *  (0.10 )^{15 - 15}

From the combination calculator  is      \left 15} \atop {}} \right.C_{15} =  1

     P(X =  15) = 1 *  0.205891 *  1

      P(X =  15) = 0.206

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