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Yuki888 [10]
3 years ago
6

Please help 4+(-10)-(-9)

Mathematics
2 answers:
Hunter-Best [27]3 years ago
5 0

Answer:

-15

Step-by-step explanation:

-10+-9=-19+4=-15

Artyom0805 [142]3 years ago
5 0
The answer is 3 if you need me to tell you how (text back)
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Select the equation in which the graph of the line has a negative slope and the y intercept equals -5
tatuchka [14]

Answer:

Step-by-step explanation:

Next time, please share the possible answer choices.

Since the slope and y-intercept are given here, we can immediately write out the slope-intercept form of the equation of this line:

y = mx + b becomes y = -1x - 5, where I have arbitrarily chosen the negative slope -1.

7 0
4 years ago
The value of the digit 5 in 634,952 is how many times the value of the 5 in 43,597
stealth61 [152]

Answer:

A}

Step-by-step explanation:

It is 10 times because it is one digit to the left that makes 10 times greater

6 0
4 years ago
Read 2 more answers
Which of the following is equal to the rational expression when x=-1 or -7? (x+1)(x-1)/(x+7)(x+1) a. x+7/x-1 b. x-1/x+7 c. x+1/x
e-lub [12.9K]

Answer:b

Step-by-step explanation:

(×+1)(×-1)

---------------

(×+1)(×+7)

=cancel (×+1) both the numerator and denominator then you are left with

(×-1)

-------

(×+7)

=(×-1)/(×+7)

5 0
3 years ago
In order to estimate the average time spent per student on the computer terminals at a local university, data were collected for
d1i1m1o1n [39]

Answer: option D

Step-by-step explanation:

The formulae for standard error = standard deviation/√n

But population standard deviation = 1.8 and sample size = n = 81

Standard error = 1.8/√81 = 1.8/9 = 0.2

4 0
3 years ago
Find four numbers that form a geometric progression such that the third term is greater than the first by 12 and the fourth is g
olchik [2.2K]

If x is the first number in the progression, and r is the common ratio between consecutive terms, then the first four terms in the progression are

\{x,xr,xr^2,xr^3\}

We want to have

\begin{cases}xr^2-x=12\\xr^3-xr=36\end{cases}

In the second equation, we have

xr^3-xr=xr(r^2-1)=36

and in the first, we have

xr^2-x=x(r^2-1)=12

Substituting this into the second equation, we find

xr(r^2-1)=12r=36\implies r=3

So now we have

\begin{cases}9x-x=12\\27x-3x=36\end{cases}\implies x=\dfrac32

Then the four numbers are

\left\{\dfrac32,\dfrac92,\dfrac{27}2,\dfrac{81}2\right\}

4 0
3 years ago
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