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Katarina [22]
3 years ago
15

Anyone want free brainliest???

Mathematics
2 answers:
otez555 [7]3 years ago
4 0

Answer:

Yes please and thanks for the points!

Step-by-step explanation:

have a great day!

andre [41]3 years ago
3 0

Answer:

thanks so much!!

Step-by-step explanation:

I need only two more brainliest until I become an Expert please help me!!

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Last month Maria hiked the 5-mile mountain trail a number of times and she hiked the 10-mile canal trail several times. Let x re
professor190 [17]
Number of times she climbed 5-mile mountain trail = x
Number of times she climbed 10-mile trail = y
total distance of the 5-mile mountain trail will be = 5*x =5x
total distance of the 10-mile mountain trail will be  = 10*y = 10y
equation  that can be used to find the number of times she hiked each trail is therefore
5x + 10y = 90
6 0
3 years ago
ILL BRAINLIEST YOU IF YOU GET IT RIGHT
IRINA_888 [86]

Answer:

b hope it helps make brainlliest ty

5 0
3 years ago
Read 2 more answers
The height of a triangle is 4 times its base. if he are of a triangle is 200cm, what is the height
uranmaximum [27]
A = (h * b) / 2
A = 200
h = 4b

200 = (b(4b) / 2
200 * 2 = b * 4b
400 = 4b^2
400 / 4 = b^2
100 = b^2
sqrt 100 = b
10 = b ..... base is 10 cm

h = 4b
h = 4(10)
h = 40 <=== height is 40 cm
3 0
3 years ago
Find the average value of f over region
yan [13]
The area of D is given by:

\int\limits \int\limits {1} \, dA = \int\limits_0^7 \int\limits_0^{x^2} {1} \, dydx  \\  \\ = \int\limits^7_0 {x^2} \, dx =\left. \frac{x^3}{3} \right|_0^7= \frac{343}{3}

The average value of f over D is given by:

\frac{1}{ \frac{343}{3} }  \int\limits^7_0  \int\limits^{x^2}_0 {4x\sin(y)} \, dydx  = -\frac{3}{343}  \int\limits^7_0 {4x\cos(x^2)} \, dx  \\  \\ =-\frac{3}{343} \int\limits^{49}_0 {2\cos(t)} \, dt=-\frac{6}{343} \left[\sin(t)\right]_0^{49} \, dt=-\frac{6}{343}\sin49
3 0
3 years ago
Val needs to find the area enclosed by the figure. The figure is made by attaching semicircles to each side of a 58​-by-58 squar
Savatey [412]

Answer:

We need to find the area of the semicircles + the area of the square.

The area of a square is equal to the square of the lenght of one side.

As = L^2 = 58m^2 = 3,364 m^2

Now, each of the semicircles has a diameter of 58m, and we have that the area of a circle is equal to:

Ac = pi*(d/2)^2 = 3.14*(58m/2)^2 = 3.14(27m)^2 = 2,289.06m^2

And the area of a semicircle is half of that, so the area of each semicircle is:

a =  (2,289.06m^2)/2 = 1,144.53m^2

And we have 4 of those, so the total area of the semicircles is:

4*a = 4* 1,144.53m^2 = 4578.12m^2

Now, we need to add the area of the square 3,364 m^2 + 4578.12m^2 = 7942.12m^2

This is nothing like the provided anwer of Val, so the numbers of val may be wrong.

4 0
3 years ago
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