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3 years ago

For what value of k, -4 is a zero of polynomial x2-x-(2k+2)?

1 answer:

5 0

Hmm
well, um
if -4 is a zero then if we subsitute -4 for x, we should get 0

so
0=(-4)²-(-4)-(2k+2)
0=16+4-2k-2
0=18-2k
2k=18
divide by 2
k=9

k=9
the value k is 9

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the expression 5n + 2 can be used to find the total cost in dollars of bowling where n is the number of games bowled and the 2 i

gogolik [260]

5(3)+2
15+2
17 monies

Just plug the amount of games in for n

8 0

3 years ago

Read 2 more answers

Experimental data are collected as:

aliina [53]

Answer:

$y = 1.00114x + 1.75243$

Step-by-step explanation:

Given

The x and y values

Required

The regression line equation

Because of the length of the given data, I will run the analysis using online tools, then analyze the result.

From the analysis, we have:

$\sum x = 5050$

$\sum y = 5231.1011$

$\bar x = 50.5$

$\bar y = 52.311$

$SSX = 83325$ --- Sum of squares

$SP = 83419.7626$ --- Sum of products

The regression equation is calculated as:

$y = ax + b$

Where:

$a = \frac{SP}{SSX}$

So, we have:

$a = \frac{83419.76}{83325}$

$a = 1.00114$

$b = \bar y - a * \bar x$

$b = 52.31 - (1.00114*50.5)$

$b = 1.75243$

So:

$y = ax + b$ becomes

$y = 1.00114x + 1.75243$

6 0

3 years ago

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Rom4ik [11]

I don’t really know what it is but you can cross out A, B, and F for sure.

6 0

3 years ago

Find the volume of the largest rectangular box in the first octant with three faces in the coordinate planes and one vertex in t

nataly862011 [7]

Let (x, y, z) be a point on the plane in the first octant. The box formed by this point has volume xyz, and you want to maximize this subject to the equation of the plane.

Use the method of Lagrange multipliers: the Lagrangian is

L(x, y, z) = xyz - λ (x + 2y + 3z - 6)

Find its critical points:

∂L/∂x = yz - λ = 0

∂L/∂y = xz - 2λ = 0

∂L/∂z = xy - 3λ = 0

∂L/∂λ = -(x + 2y + 3z - 6) = 0

Solving the first three equations for λ gives

λ = yz = xz/2 = xy/3

Solve these equations for y and z :

• yz = xz/2 => y = x/2 => 2y = x

• yz = xy/3 => z = x/3 => 3z = x

Substitute these solutions into the last equation and solve for x, then again for y and z :

x + 2y + 3z - 6 = 3x - 6 = 0 => 3x = 6 => x = 2, y = 1, z = 2/3

At this critical point, the maximum volume is

xyz = 2*1*2/3 = 4/3

4 0

3 years ago

Simplify the expression. . 1 V 3.0 2

Vlad [161]

Answer:

81x^4/16 (81x to the fourth over 16)

Step-by-step explanation:

First you apply the exponent rule: (a/b)^c -> a^c/b^c

So it looks like this: 3x^2/4^2

Then you apply the exponent to the whole thing, and 3^4 is 81, x^4 stays like that, and 2^4 is 16

You can't simplify any more after that so that's your answer

Hope this helps!

5 0

3 years ago