Answer:
If the population grows by 4% each year then
the population in any given year is 104% of
the previous year or 1.04 times as much
P(t) = P0(1.04)t
P(t) is population at time t years
P0 = initial population = 11,000
t = number of years = 15
P(15) = 11,000(1.04)15
P(15) = 19,810 people
Step-by-step explanation:
A pair of perpendicular lines would be line CF and line AJ.
Line BC and line AJ are NOT perpendicular because when a pair of lines are perpendicular, all angles become 90 degrees. It is obvious, in the case, if you were to slide line BC on top of line AJ, the angles will not equal 90 degrees.
Answer:
Exactly 16%.
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
The mean of a certain set of measurements is 27 with a standard deviation of 14.
This means that 
The proportion of measurements that is less than 13 is
This is the p-value of Z when X = 13, so:

has a p-value of 0.16, and thus, the probability is: Exactly 16%.
Answer:
32
Step-by-step explanation:
Plug in 4 for c.
(c³)/2 = (4³)/2
First, solve the parenthesis, then divide. Multiply:
4³ = 4 * 4 * 4 = 16 * 4 = 64
Next, divide:
64/2 = 32
32 is your answer.
~
The bearing of the individuals from each other are as indicated below;
- S45°E
- N25°E
- S65°E
- S15°E
- N45°E
- N75°E
<h3>What is bearing of Henley from Dinder?</h3>
It follows from the task content that the bearing of the individuals from each other are expected to be determined.
a) For Henley from Dinder; it follows from observation that Henley is; S45°E of Dinder's position.
b) For Dinder from Weare; it follows from observation that Dinder is; N25°E of Weare's position.
c) For Weare from Dinder; it follows from observation that Weare is; S65°E of Dinder's position.
d) For Weare from Henly; it follows from observation that Weare is; S15°E of Dinder's position.
e) For Dinder from Henly; it follows from observation that Dinder is; N45°E of Henly's position.
f) For Henly from Weare; it follows from observation that Henly is; N75°E of Weare's position.
Read more on bearing;
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