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Agata [3.3K]
3 years ago
9

Find the area of the triangle that has a base of 16 yd and a height of 9 yd.

Mathematics
1 answer:
kherson [118]3 years ago
7 0
Area=1/2Bh
Area=1/2(16)(9)
Area=(8)(9)
Area=72yd
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Which statement describes the function y = axn when a = 1 and n is odd?
kiruha [24]

Answer:

The graph is symmetric about the origin.

The graph does not pass through the origin.

Step-by-step explanation:

We're given:

  • the function y=axn
  • a = 1
  • n is odd

Because a = 1, then the given function can be rewritten as y = n.

  • The graph opens down

The function y = n will produce a horizontal line. Any function in the form of y = a single number, such as 4 or 9.3 will produce a horizontal line.

  • The graph is symmetric about the origin.

This is true, given the graph is a horizontal line.

  • The graph does not pass through the origin.

This is also true. We're given that n is an odd number. The graph will only pass through the origin if n = 0, and 0 is even.

  • The graph has more than one x-intercept.

This would only be true when n = 0, and this isn't possible. So, no.

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2 years ago
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Sarah's Shipping and Ryan's Mail Services both ship packages. Sarah's trucks
algol [13]

Answer:I think 11

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8 0
3 years ago
In a certain region of space, the potential is given by v=2x−5x2y 3yz2. How much is the magnitude of the electric field at point
Masja [62]

The magnitude of the electric field at the point (-2, 2, 0) is 46.52 V/m

<h3>How to calculate the electric field?</h3>

Since in a certain region of space, the potential is given by v = 2x − 5x²y 3yz²,

The electric field, E = -grad(V) where grad(V) = (dV/dx)i + (dV/dy)j + (dV/dz)k

Since V = 2x − 5x²y + 3yz²

dV/dx = d(2x − 5x²y + 3yz²)/dx

= d2x/dx - d5x²y/dx + d3yz²/dx

= 2 - 10xy + 0

= 2 - 10xy

dV/dy = d(2x − 5x²y + 3yz²)/dy

= d2x/dy - d5x²y/dy + d3yz²/dy

= 0 - 5x² + 3z²

=  - 5x² + 3z²

dV/dz = d(2x − 5x²y + 3yz²)/dz

= d2x/dz - d5x²y/dz + d3yz²/dz

= 0 - 0 + 6z

=  6z

<h3>The electric field</h3>

So, E = -grad(V)

= -[(dV/dx)i + (dV/dy)j + (dV/dz)k]

= -[(2 - 10xy)i + (- 5x² + 3z²)j + (6z)k]

So, the electric field at (-2, 2, 0) is

E = -[(2 - 10xy)i + (- 5x² + 3z²)j + (6z)k]

E = -[(2 - 10(-2)(2))i + (- 5(2)² + 3(0)²)j + (6(0))k]

E = -[(2 + 40)i + (- 5(4) + 0)j + (0)k]

E = -[42i + (-20 + 0)j + (0)k]

E = -[42i - 20j + 0k]

E = -42i + 20j - 0k

<h3>The magnitude of the electric field</h3>

So, the magnitude of E at (-2, 2, 0) is

|E| = √[(-42)² + 20² + 0²]

=  √[1764 + 400 + 0]

= √2164

= 46.52 V/m

So, the magnitude of the electric field at the point (-2, 2, 0) is 46.52 V/m

Learn more about electric field here:

brainly.com/question/25751825

#SPJ12

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faltersainse [42]
The answer is 3√5. You use the distance formula: √((x2-x1)^2+(y2-y1)^2)
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. Mark has $20 in his bank account. He saves $5 each week. How much money does Mark have in his account after 9 weeks? Use x to
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Answer:

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Step-by-step explanation:

id k how to explain but since he saves 5 dollars he basically has 15 dollars in his bank account u just need to multiply 15 with however many weeks he saves up for

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