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grandymaker [24]

3 years ago

12

A cylinder with a radius of 4 cm and a height of 6 cm is inside of a sphere with a radius of 10 cm. How much space is inside the

sphere, but outside a cylinder? Round to the nearest tenth if necessary. Use 3.14 for pi.

1 answer:

Musya8 [376]3 years ago

3 0

The answer is 33.33 .....

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A 30L tank contains 20L of a salt/water mixture with 4kg of salt. We begin pumping a mixture with.08 kg/L concentration into the

gregori [183]

Answer:

qgog]nh[5hlTMetfrgt[ybpfd

Step-by-step explanation:

klj ;l,;gg/l.,sjmfehgads vcb

8 0

2 years ago

If 10 is to the second power then divided by 3 and multiplied by 7 what’s the answer?

Savatey [412]

First, 10 to the second power equals to 100. 100 divided by 3 equals to 33.33. 33.33 x 7 equals to 233.33. So the answer is 233.33.

4 0

3 years ago

Read 2 more answers

8-5c=-37 help please :)

ladessa [460]

Answer:

c=9

Step-by-step explanation

8-5c=-37

-37-8= -5c

-45= -5c

-45/-5=c

c=9

6 0

3 years ago

Read 2 more answers

Animals and people that take in more energy than they expend will get fatter. Here are data on 12 rhesus monkeys: 6 lean monkeys

In-s [12.5K]

Answer:

mean lean body mass of the lean monkeys = 8.4kg

mean lean body mass of the obese monkeys = 10.4kg

Step-by-step explanation:

a) Mean = Sum of Body mass/number of body mass

For lean monkeys, mean = (6+7.5+9.2+9.7+9.1+9.1)/6

Mean = 50.6/6

Mean = 8.4

b)

for obese monkeys, mean = (8+9.1+10.3+12+11.9+11.2)/6

Mean = 62.5/6

Mean = 10.4

3 0

3 years ago

Plz help me!!!!!!!!!

Over [174]

Answer: $\bold{\dfrac{4\pm \sqrt{6}}{2}}$

<u>Step-by-step explanation:</u>

$\dfrac{3}{y-2}-2=\dfrac{1}{y-1}\\\\\\\text{Multiply by the LCD (y-2)(y-1) to clear the denominator:}\\\\\dfrac{3}{y-2}(y-2)(y-1)-2(y-2)(y-1)=\dfrac{1}{y-1}(y-2)(y-1)\\\\\\3(y-1)-2(y-2)(y-1)=1(y-2)\\\\3y-3-2(y^2-3y+2)=y-2\\\\3y-3-2y^2+6y-4=y-2\\\\-2y^2+9y-7=y-2\\\\0=2y^2-8y+5\quad \rightarrow \quad a=2,\ b=-8,\ c=5\\\\\\\text{Quadratic formula is: }x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\\x=\dfrac{-(-8)\pm \sqrt{(-8)^2-4(2)(5)}}{2(2)}\\\\\\.\ =\dfrac{8\pm \sqrt{64-40}}{2(2)}$

$.\ =\dfrac{8\pm \sqrt{24}}{2(2)}\\\\\\.\ =\dfrac{8\pm 2\sqrt{6}}{2(2)}\\\\\\.\ =\dfrac{4\pm \sqrt{6}}{2}$

7 0

3 years ago