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3 years ago

If a cell did not have these parts, it might have difficulty moving around.

Mathematics

1 answer:

kobusy [5.1K]3 years ago

5 0

<span>a. cilia and flagella</span>

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In which quadrant does θ lie given that sinθ < 0 and cosθ < 0? Thank You!

monitta

Answer:

The origin.

Step-by-step explanation:

0 belongs in none of these quadrants but in the origin. The origin is the center dot in the middle of all quadrants.

8 0

2 years ago

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Can someone pls help me out

USPshnik [31]

Answer:

It is a money market account. So answer A.

Step-by-step explanation:

3 0

3 years ago

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The pool at "splash around" is open for 14 weeks during the summer. you can swim for $6 a session, or you can buy a membership f

Ratling [72]

Let

x--------> the number of sessions

y-------> the total payment

we know that

without membership:

$y=6x$ --------> equation $1$

with membership:

$y=100+4x$ --------> equation $2$

using a graph tool------> resolve the system of equations

see the attached figure

the solution is the point $(50,300)$

that means

For $x=50\ sessions$

the cost is $\$300$ in both forms

to justify buying the membership

$x > 50\ sessions$

therefore

<u>the answer is</u>

$x > 50\ sessions$

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4 years ago

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The mass of Earth is made up of these parts.

Elena-2011 [213]

Answer:

1. atmosphere

2.oceans

3.crust

4.inner core

5. outer core

6.mantle

8 0

3 years ago

A ball is thrown from an initial height of 1 meter with an initial upward velocity of 15m/s. The ball's height h (in meters) aft

lakkis [162]

$\bf \stackrel{\textit{ball's height}~\hfill }{\stackrel{\downarrow }{h}=1+15t-5t^2}\implies \stackrel{\textit{ball's height}~\hfill }{\stackrel{\downarrow }{6}=1+15t-5t^2}\implies 0=-5+15t-5t^2 \\\\\\ ~~~~~~~~~~~~\textit{using the quadratic formula} \\\\ \stackrel{\stackrel{a}{\downarrow }}{5}t^2\stackrel{\stackrel{b}{\downarrow }}{-15}t\stackrel{\stackrel{c}{\downarrow }}{+5}=0 \qquad \qquad t= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a}$

$\bf t=\cfrac{-(-15)\pm\sqrt{(-15)^2-4(5)(5)}}{2(5)}\implies t=\cfrac{15\pm\sqrt{225-100}}{10} \\\\\\ t=\cfrac{15\pm\sqrt{125}}{10}\implies t=\cfrac{15\pm\sqrt{5^2 \cdot 5}}{10}\implies t=\cfrac{\stackrel{3}{~~\begin{matrix} 15 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\pm ~~\begin{matrix} 5 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~\sqrt{5}}{\underset{2}{~~\begin{matrix} 10 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}$

$\bf t=\cfrac{3\pm \sqrt{5}}{2}\implies t= \begin{cases} \frac{3+ \sqrt{5}}{2} \approx 2.618\\\\ \frac{3- \sqrt{5}}{2}\approx 0.382 \end{cases}$

8 0

3 years ago