(x+5)*7=133
7x+35=133
7x=98
x=98/7
x=14
Answer:
If the first die is a 5, the second must be 5 or more in order to have a sum of at least ten.
Assuming it is a six sided die, the two values that would make this true are 5 and 6.
2 values/6 possible would be a probability of 2/6, which simplifies to 1/3
Final answer: 1/3
Step-by-step explanation:
Answer:−x2−6xy+8y2+9yz−12
The zeros are (7,0) and (-6,0).