6x^4+4x^2 what is the degree and number of terms?

Mathematics

1 answer:

Andrew [12]2 years ago

4 0

The degree is "4" and the number of terms is "1"

You might be interested in

Consider kite ABCD.

bixtya [17]

Answer: x=5, y=22 C.

Step-by-step explanation:

I just did the quiz

7 0

2 years ago

Read 2 more answers

For X a binomial random variable with n=5 and p=1/4, answer the following

mash [69]

Recall that for $X\sim\mathrm{Bin}(n,p)$ , i.e. a random variable $X$ following a binomial distribution over $n$ trials and with probability parameter $p$ ,

$\mathbb P(X=x)=f_X(x)=\begin{cases}\dbinom nx p^x(1-p)^{n-x}&\text{for }x\in\{0,1,\ldots,n\}\\\\0&\text{otherwise}\end{cases}$

So you have

$\mathbb P(X=2)=\dbinom52\left(\dfrac14\right)^2\left(1-\dfrac34\right)^{5-2}=\dfrac{135}{512}\approx0.26$

$\mathbb P(2\le X\le4)=\displaystyle\sum_{x=2}^4\mathbb P(X=x)$
$=\dbinom52\left(\dfrac14\right)^2\left(1-\dfrac14\right)^{5-2}+\dbinom52\left(\dfrac14\right)^3\left(1-\dfrac14\right)^{5-3}+\dbinom52\left(\dfrac14\right)^4\left(1-\dfrac14\right)^{5-4}$
$=\dfrac{375}{1024}\approx0.37$

The expected value of $X\sim\mathrm{Bin}(n,p)$ is simply $np$ , while the standard deviation is $\sqrt{np(1-p)}$ . In this case, they are $\dfrac54=1.25$ and $\sqrt{\dfrac{15}{16}}\approx0.97$ , respectively.

7 0

2 years ago

The area of a rectangle is 27 m^2 , and the length of the rectangle is 3 m less than twice the width. Find the dimensions of the

vagabundo [1.1K]

Let $L$ be the length of the rectangle and $W$ be the width. In the problem it is given that $L=2W-3$ . It is also given that the area $LW=27$ . Substituting in the length in terms of width, we have $W(2W-3)=27 \\ 2W^2-3W-27=0 \\ (2W-9)(W+3)=0$ . Using the zero product property, $2W-9=0 \text{ or } W+3=0$ . Solving these we get the width $W=4.5 \text{ or } -3$ . However, it doesn't make sense for the width to be negative, so the width must be $\boxed{4.5 \text{ m}}$ . From that we can tell the length $L=2(4.5)-3=\boxed{6 \text{ m}}$ .