To solve this problem you must apply the proccedure shown below:
1. The problem asks for the area of a cross section that is parallel <span>to face ABCD. As is parallel to that face, you have can calculate its area as following:
A=12 cm x 6 cm
2. Therefore, the result is:
A=72 cm</span>²
The answer is: T<span>he area of a cross section that is parallel to face ABCD is 72 cm</span>².
Answer: 37 1/3
Step-by-step explanation:
14/1÷3/8=?
Dividing two fractions is the same as multiplying the first fraction by the reciprocal (inverse) of the second fraction.
Take the reciprocal of the second fraction by flipping the numerator and denominator and changing the operation to multiplication. Then the equation becomes
14/1 × 8/3=?
For fraction multiplication, multiply the numerators and then multiply the denominators to get
14×8/1×3 = 112/3
This fraction cannot be reduced.
The fraction
112/3
is the same as
112÷3
Convert to a mixed number using
long division so
112/3=37 1/3
Therefore:
14/1 ÷ 3/8=37 1/3
Answer:
85.6cm
Step-by-step explanation:
Area of a triangle =1/2*b*h
Where base=19.5cm while the height is 8 4/5 = 8.8
Area = 1/2 * 19.5cm * 8.8cm
Area = 171.6cm/2
Area=85.6cm
Answer:
22.75
Step-by-step explanation:
you substitute the 7 in for c and d. Following PEMDAS, you would then do (1/4) multiplied by 7 and 3 times 7. add those 2 together and you get 22.75 :)
Answer: 54.4 mph
Step-by-step explanation:
First find the distance to the train station. If it took Carlos 4 hours to come back driving at 68 mph, the distance is:
= Speed * time
= 68 * 4
= 272 miles
This means that Carlos drove for 5 hours to cover 272 miles the first time. His average speed was therefore:
= Distance / time
= 272/5
= 54.4 mph