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Artemon [7]
3 years ago
6

I have a math problem I am having issues with, what is the order of operations in a question like this? and how would I go about

solving it?
12x>9(2x-3)-15
Mathematics
1 answer:
tamaranim1 [39]3 years ago
6 0
Parenthesis, exponents, multiplication and division, addition and subtraction
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PLEASE HELP
gayaneshka [121]
Area would be 66

You would simply multiple the width be the height to get your area!
5 0
2 years ago
The total sales of a company (in millions of dollars) t months from now are given by S(t) = 0.03t3 + 0.5t2 + 9t + 4. Find S'(t).
mars1129 [50]

Answer:

S(2) = 24.24. This means that in the second month, the company will sell 24.24 millions of dollars in total.

S'(2) = 11.36. This means that in the second month the total sales will increase in 11.36 millions of dollars from the previous month.

d. The total sales 11 months from now will be $203.43 million dollars.

Step-by-step explanation:

The total sales of the company, in millions of dollars is given by the following formula:

S(t) = 0.03t^{3} + 0.5t^{2} + 9t + 4

This function has the following derivative, which represents the variation in relation to the previous month.

S'(t) = 0.09t^{2} + t + 9

Find S(2) and S'(2)

S(t) = 0.03t^{3} + 0.5t^{2} + 9t + 4

S(2) = 0.03*(2)^{3} + 0.5*(2)^{2} + 9*2 + 4 = 24.24

S(2) = 24.24. This means that in the second month, the company will sell 24.24 millions of dollars in total.

S'(t) = 0.09t^{2} + t + 9

S'(2) = 0.09*2^{2} + 2 + 9 = 11.36

S'(2) = 11.36. This means that in the second month the total sales will increase in 11.36 millions of dollars from the previous month.

Choose the correct interpretation of S(11)=203.43.

S represents total sales, and S(11) is the total sales 11 months from now.

So the correct answer is:

d. The total sales 11 months from now will be $203.43 million dollars.

7 0
3 years ago
The total cost of 5 boxes of pasta is $13.00. Each box of pasta costs the same amount.
schepotkina [342]

Answer:

$2.60

Step-by-step explanation:

13.00÷5=2.6

6 is in tens placement

8 0
2 years ago
BRAINLIESTTT ASAP!! PLEASE HELP ME :)
Lostsunrise [7]

Answer:

See below  

Step-by-step explanation:

(a) Field lines

A negatively charged particle has an electric field associated with it.

The field lines spread out radially from the centre of the point. They are represented by arrows pointing in the direction that a positive charge would move if it were in the field.

Opposite charges attract, so the field lines point toward the centre of the particle.

For an isolated negative particle, the field lines would look like those in Figure 1 below.

If two negative charges are near each other, as in Figure 2, the field lines still point to the centre of charge.

A positive charge approaching from the left is attracted to both charges, but it moves to the closer particle on the left.

We can make a similar statement about appositive charge approaching from the left.

Thus, there are few field lines in the region between the two particles.

(b) Coulomb's Law

The formula for Coulomb's law is

F = (kq₁q₂)/r²

It shows that the force varies inversely as the square of the distance between the charges.

Thus, the force between the charges decreases rapidly as they move further apart.

5 0
3 years ago
Please help! This assignment is due soon! (In The photo)
eimsori [14]

Answer

Elena must have substracted 1/2x from both sides of the equation.

Lin must have multiplied both sides of the equation by 2

Explanation

The equation given is

\frac{1}{2}x+3=\frac{7}{2}x+5

For Elena to have arrived at

3=\frac{7}{2}x-\frac{1}{2}x+5

Then Elena must have substracted 1/2x from both sides of the equation.

That is;

\begin{gathered} \frac{1}{2}x+3=\frac{7}{2}x+5 \\ \text{Substracting }\frac{1}{2}x\text{ from both sides of the equation will give Elena first step} \\ \frac{1}{2}x+3-\frac{1}{2}x=\frac{7}{2}x+5-\frac{1}{2}x \\ 3=\frac{7}{2}x-\frac{1}{2}x+5 \end{gathered}

For Lin to have arrived at

x+6=7x+10

It shows Lin must have multiplied both sides of the equation by 2

That is;

\begin{gathered} \frac{1}{2}x+3=\frac{7}{2}x+5 \\ \text{Multiply both sides of the equation by the lowest common mutiple } \\ \text{of the denominator which is 2.} \\ \frac{1}{2}x(2)+3(2)=\frac{7}{2}x(2)+5(2) \\ x+6=7x+10 \end{gathered}

4 0
1 year ago
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