9514 1404 393
Answer:
P(0, 4), Q(-3, 0)
Step-by-step explanation:
To find the y-coordinate of P, replace x with 0 and solve for y:
3y = 12
y = 4 . . . . . divide by 3
__
To find the x-coordinate of Q, replace y with 0 and solve for x:
-4x = 12
x = -3 . . . . . divide by -4
Then the intercepts are P(0, 4) and Q(-3, 0). The line is drawn through those points for the indicated values of x.
We can answer the first part of the question not taking intersecting function into account. The domain of is all the numbers, x∈(-∞, +∞) and the range is y∈(-∞, 36]. We can observe these results with the help of a graph, as well. Since we are talking about the rainbow, the values above the ground level will make sense. In this case, we will take into account the range as it changes between 0 and 36, included and the domain between -6 and 6. Here (0;36) is the y-intercept and (-6;0) and (6;0) are the x-intercepts of the parabola.
Since in our problem, the linear function that intersects parabola is not given, we have to provide it by ourselves according to the conditions of the problem. It could be any line intersecting parabola in two points. One important point is that the y-intercept has to be no more than 36. Considering these conditions, we can set our linear function to be . We can observe the points that we included in the table (they have been given with orange dots in the graph and the table is attached below). We can see that the values of the function (values of y) are positive. Indeed, we are discussing the part of the rainbow above the ground level.
The system of equations with linear and quadratic functions has got two solutions and we can observe that result from the graph. The solutions are (-5.823; 2.088) and (5.323; 7.662). The solutions are the intersection points.
