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3 years ago

Select all ratios equivalent to 20:12 ... 1)10:6 2)15:9 3)3:2

Mathematics

1 answer:

ioda3 years ago

3 0

20:12

divide both numbers by 2

10:6

divide by 2 again

5:3

multiply this by 3

15:9

choices 1 and 2 are correct

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The graph of g(x), shown below, is a vertical shift of the graph of f(x) = 2x.

4vir4ik [10]

The equation which represents the given graph g(x) is 2ˣ-1.

<h3>What is Equation?</h3>

Equations are mathematical statements containing two algebraic expressions on both sides of an 'equal to (=)' sign.

Here, given graph passes through origin.

Put x = 0 in all the given equation and verify which equations gives result as zero.

Put x = 0 in option A

g(0) = 2⁰⁺¹ = 2 ≠ 0

in option B

g(0) = 2⁰-1 = 1 - 1 = 0

Thus, option B g(x) = 2ˣ-1 is the correct expression for the given graph.

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2 years ago

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2 years ago

Read 2 more answers

Arrange the pairs of points in increasing order of the slopes of the lines joining them. (15, 30) and (20, 40)

gavmur [86]

Answer: m1 = 0.5

M2= 0.375

M3 = 2.25

M4 = 3.0

M5 = 13.5

M6 = 0.285

M7 = 7.0

Step-by-step explanation:

(20,40)-(15,30)=(5,10), m1=5/10=0.5

(18,48)-(12,32)=(6,16), m2=3/8=0.375

(72,32)-(27,12)=(45,20), m3=9/4=2.25

(60,20)-(45,15)=(15,5), m4=3.0

(243,18)-(27,2)=(216,16), m5=27/2=13.5

(24,84)-(18,63)=(6,21), m6=2/7=0.285...

(84,12)-(63,9)=(21,3), m7=7.0

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3 years ago

Please help!! What Find the Error and explain why it is wrong!

Nata [24]

Answer:

First image attached

The error was done in Step E, because student did not multiply $2\cdot x -8$ by the negative sign in numerator. Step E must be $\frac{2\cdot x -5}{(x+4)\cdot (x-4)}$ .

Second image attached

The error was done in Step C, because the student omitted the $2\cdot a \cdot b$ of the algebraic identity $(a+b)^{2} = a^{2}+2\cdot a\cdot b +b^{2}$ . Step C must be $5\cdot x = x^{2}+4\cdot x + 4$

Step-by-step explanation:

First image attached

The error was done in Step E, because student did not multiply $2\cdot x -8$ by the negative sign in numerator. The real numerator in Step E should be:

$3-(2\cdot x -8)= 3-2\cdot x+8 = 11-2\cdot x$

Hence, Step E must be $\frac{2\cdot x -5}{(x+4)\cdot (x-4)}$ .

Second image attached

The error was done in Step C, because the student omitted the $2\cdot a \cdot b$ of the algebraic identity $(a+b)^{2} = a^{2}+2\cdot a\cdot b +b^{2}$ . Step C must be $5\cdot x = x^{2}+4\cdot x + 4$

And further steps are described below:

Step D

$x^{2}-x+4 = 0$