Hello!
Remember that the symbols: ≤ and ≥ are graphed as a solid line. While the symbols: < and > are graphed as a dotted line.
Also, before graphing, it would be better to convert both equations to slope-intercept form.
y ≤ x + 1 is already in slope-intercept form.
y + x ≤ -1 is not written in slope-intercept form. (Slope-intercept form: y = mx + b)
y + x ≤ - 1 (subtract x from both sides)
y ≤ -x - 1
Graphing those lines, you get the graph below. You can see that Part C best represents the solution set systems of inequalities, because that is where both of the shaded lines intersect.
Answer: Part C
Answer:
x=3
Step-by-step explanation:
First would need to convert the radical into a number.
And since if you have a perfect square of a radical it goes outside the square root sign, you would take the 3 and square it to make 9 and then take the 2 inside the square root sign and multiply so you have the square root of 18|
Since we have 
as the Leg c we would need to square it, squaring a square root sign would just cause them to be cancelled out and you being left with 18, afterwards find the square of 3, which is 9
18-9=9
square root of 9 = 3
Answer: x=1
Step-by-step explanation: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
3*x+2*(5*x-3)-(7)=0
3x + 2 • (5x - 3)) - 7 = 0
Pull out like factors :
13x - 13 = 13 • (x - 1)
13 = 0
A a non-zero constant never equals zero.
Solve : x-1 = 0
Add 1 to both sides of the equation :
x = 1
Answer:
10,000
Step-by-step explanation:
In order to round numbers we look at the number to the right of whatever we are rounding to. So in this case we are rounding to the nearest thousand so we look at the number to the right of the thousands which is the hundred in this case. If that number is a 1-4 we round down and if that number is a 5-9 we round up. In this case the number to the right is a 9 so we will round up. The nearest thousand above 9991 is 10,000 so that is what we will round to
Answer:
<em>- 2</em>
Step-by-step explanation:
f(1) = - 2
