answer : False
The measure of a tangent-tangent angle is one - half the difference of the measures of the intercepted arcs.
The diagram is attached below
AB and BC are the two tangents
By exterior angle theorem
∠3 = ∠2 + ∠4
So ∠2 = ∠3 - ∠4
Now we find angle 3 and 4, we know when a chord and tangent intersect at a point then the measure of angle is one half of measure of intercepted arc
∠3 = 
∠4 = 
∠2 = ∠3 - ∠4
∠2 = -
∠2 = 
The measure of a tangent-tangent angle is one half the difference of the measures of the intercepted arcs.
First, it is important to understand that any equation that is x=some number is just a vertical line that hits the x-axis at the given number. For example, x=-2 would be a vertical line hitting the x-axis at -2. Therefore, the line we are trying to identify would also be vertical (and have the form x=some number) because we know the lines are parallel. Then, since we're given the point (-5,4), we know the line needs to hit the x-axis at -5, therefore the equation would be x=-5.
I hope this helps.
2n-12n-15=-6n+18-1
-10n-15=-6n+17
+10n. +10n
-15=4n+17
-17. -17
-32=4n
/4 /4
-8=n
