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Natasha2012 [34]

3 years ago

12

9/10 greater or less than 6/8

2 answers:

lesya692 [45]3 years ago

8 0

9/10 is greater than 6/8

Setler79 [48]3 years ago

8 0

First, you have to find a common denominator. You could do 9/10 times 5 to get 45/50 and 6/8 times 5 to get 30/40. Compare the numerators.

45 > 30, therefore 9/10 is greater than 6/8.

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Help please!!!! thank you in advance. asap too

qaws [65]

You can check the following
C=4
C=5
C=11

4 0

3 years ago

9. Which of the following do you need to know to determine the surface area and volume of a sphere?

Alexxx [7]

Answer:

A: radius of the sphere

Step-by-step explanation:

The formula for surface area is A = 4πr^2

With r being the radius and A the surface area.

For volume it is

V= (4/3)πr^3

6 0

3 years ago

Please help me (9-7×3+4)^2

kherson [118]

(9 - 7 × 3 + 4)²
(9 - 21 + 4)²
(9 - 17)²
(-12)²
144

5 0

4 years ago

Suppose there are 4 defective batteries in a drawer with 10 batteries in it. A sample of 3 is taken at random without replacemen

SSSSS [86.1K]

Answer:

a.) 0.5

b.) 0.66

c.) 0.83

Step-by-step explanation:

As given,

Total Number of Batteries in the drawer = 10

Total Number of defective Batteries in the drawer = 4

⇒Total Number of non - defective Batteries in the drawer = 10 - 4 = 6

Now,

As, a sample of 3 is taken at random without replacement.

a.)

Getting exactly one defective battery means -

1 - from defective battery

2 - from non-defective battery

So,

Getting exactly 1 defective battery = ⁴C₁ × ⁶C₂ = $\frac{4!}{1! (4 - 1 )!}$ × $\frac{6!}{2! (6 - 2 )!}$

= $\frac{4!}{(3)!}$ × $\frac{6!}{2! (4)!}$

= $\frac{4.3!}{(3)!}$ × $\frac{6.5.4!}{2! (4)!}$

= $4$ × $\frac{6.5}{2.1! }$

= $4$ × $15$ = 60

Total Number of possibility = ¹⁰C₃ = $\frac{10!}{3! (10-3)!}$

= $\frac{10!}{3! (7)!}$

= $\frac{10.9.8.7!}{3! (7)!}$

= $\frac{10.9.8}{3.2.1!}$

= 120

So, probability = $\frac{60}{120} = \frac{1}{2} = 0.5$

b.)

at most one defective battery :

⇒either the defective battery is 1 or 0

If the defective battery is 1 , then 2 non defective

Possibility = ⁴C₁ × ⁶C₂ = 60

If the defective battery is 0 , then 3 non defective

Possibility = ⁴C₀ × ⁶C₃

= $\frac{4!}{0! (4 - 0)!}$ × $\frac{6!}{3! (6 - 3)!}$

= $\frac{4!}{(4)!}$ × $\frac{6!}{3! (3)!}$

= 1 × $\frac{6.5.4.3!}{3.2.1! (3)!}$

= 1× $\frac{6.5.4}{3.2.1! }$

= 1 × 20 = 20

getting at most 1 defective battery = 60 + 20 = 80

Probability = $\frac{80}{120} = \frac{8}{12} = 0.66$

c.)

at least one defective battery :

⇒either the defective battery is 1 or 2 or 3

If the defective battery is 1 , then 2 non defective

Possibility = ⁴C₁ × ⁶C₂ = 60

If the defective battery is 2 , then 1 non defective

Possibility = ⁴C₂ × ⁶C₁

= $\frac{4!}{2! (4 - 2)!}$ × $\frac{6!}{1! (6 - 1)!}$

= $\frac{4!}{2! (2)!}$ × $\frac{6!}{1! (5)!}$

= $\frac{4.3.2!}{2! (2)!}$ × $\frac{6.5!}{1! (5)!}$

= $\frac{4.3}{2.1!}$ × $\frac{6}{1}$

= 6 × 6 = 36

If the defective battery is 3 , then 0 non defective

Possibility = ⁴C₃ × ⁶C₀

= $\frac{4!}{3! (4 - 3)!}$ × $\frac{6!}{0! (6 - 0)!}$

= $\frac{4!}{3! (1)!}$ × $\frac{6!}{(6)!}$

= $\frac{4.3!}{3!}$ × 1

= 4×1 = 4

getting at most 1 defective battery = 60 + 36 + 4 = 100

Probability = $\frac{100}{120} = \frac{10}{12} = 0.83$

3 0

3 years ago

-3(3+x)+4(x-6)=-4 Please help me with this question

dsp73

Answer:

$\boxed{ \bold{ \huge{ \sf{x = 29}}}}$

Step-by-step explanation:

$\sf{ - 3(3 + x) + 4(x - 6) = - 4 }$

Distribute -3 through the parentheses

Similarly, Distribute 4 through the parentheses

⇒ $\sf{ - 9 - 3x + 4x - 24 = - 4}$

Collect like terms

⇒ $\sf{x - 9 - 24 = - 4}$

Calculate

⇒ $\sf{x - 33 = - 4}$

Move 33 to right hand side and change it's sign

⇒ $\sf{x = - 4 + 33}$

Calculate

⇒ $\sf{x = 29}$

Hope I helped!

Best regards!!

7 0

4 years ago