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3 years ago

How do you evaluate a logarithm

Mathematics

1 answer:

seraphim [82]3 years ago

4 0

Answer:

If you want to solve a logarithm, you can rewrite it in exponential form and solve it that way

Step-by-step explanation:

i don't know if this will help but i tried

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What is the volume, in cubic in, of a cylinder with a height of 8 in and a base radius of

densk [106]

Answer:

V=100.5

Step-by-step explanation:

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5 0

2 years ago

15.7/6.28 what is the answer how do you do it

Andrew [12]

Simply divide 15.7 by 6.28 to get 2.5 :) easy peasy pumpkin pie

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3 years ago

Some Geometry problems I need some help with!

drek231 [11]

Answer:

When a 2-D circle is rotated around a line that it does not touch. What is the name of the resulting figure?

The answer is annulus

A sphere with radius 16 m is cut by a plane though it’s a great circle. What is the best description of the cross section that is shown?

B. A circle with radius 16 m

8 0

4 years ago

Suppose you have 18 objects (10 of type A, 5 of type B, and 3 of type C). Objects of type A are indistinguishable from each othe

Paladinen [302]

Answer:

$\binom{18}{5}= 8568$

Step-by-step explanation:

Note that we have in total 18 items. Even though we are given information regarding the amounts of items per type, the general question asks the total number of ways in which you can pick 5 out of the 18 objects, without any restriction on the type of chosen items. Therefore, the information regarding the type is unnecessary to solve the problem.

Recall that given n elements, the different ways of choosing k elements out of n is given by the binomial coefficient $\binom{n}{k})$ .

Therefore, in this case the total number of ways is just $\binom{18}{5}=8568$

5 0

3 years ago

Read 2 more answers

Two cards are selected from a standard deck of 52 playing cards. The first card is not replaced before the second card is select

Blizzard [7]

Answer:

Probability is: $\frac{\textbf{13}}{\textbf{51}}$

Step-by-step explanation:

From a deck of 52 cards there are 26 black cards. (Spades and Clubs).

Also, there are 26 red cards. (Hearts and Diamonds).

First, we determine the probability of drawing a black card.

P(drawing a black card) = $\frac{number \hspace{1mm} of \hspace{1mm} black \hspace{1mm} cards}{total \hspace{1mm} number \hspace{1mm} of \hspace{1mm} cards}$ $= \frac{26}{52} = \frac{\textbf{1}}{\textbf{2}}$

Now, since we don't replace the drawn card, there are only 51 cards.

But the number of red cards is still 26,

∴ P(drawing a red card) = $\frac{number \hspace{1mm} of \hspace{1mm} red \hspace{1mm} cards}{total \hspace{1mm} number \hspace{1mm}of \hspace{1mm} cards}$ $= \frac{26}{51}$

Now, the probability of both black and red card = $\frac{1}{2} \times \frac{26}{51}$

$= \frac{\textbf{13}}{\textbf{51}}$

Hence, the answer.

5 0

3 years ago