Looking for gf pls needed

Mathematics

1 answer:

Allisa [31]3 years ago

4 0

I’m right here……………….

You might be interested in

What is the value of cosθ given that (−2, −3) is a point on the terminal side of θ ?

snow_tiger [21]

Answer:

-0.555

Step-by-step explanation:

The terminal point of the vector in this problem is

(-2,-3)

So, it is in the 3rd quadrant.

We want to find the angle $\theta$ that gives the direction of this vector.

We can write the components of the vector along the x- and y- direction as:

$v_x = -2\\v_y = -3$

The tangent of the angle will be equal to the ratio between the y-component and the x-component, so:

$tan \theta = \frac{v_y}{v_x}=\frac{-3}{-2}=1.5\\\theta=tan^{-1}(1.5)=56.3^{\circ}$

However, since we are in the 3rd quadrant, the actual angle is:

$\theta=180^{\circ} + 56.3^{\circ} = 236.3^{\circ}$

So now we can find the cosine of the angle, which will be negative:

$cos \theta = cos(236.3^{\circ})=-0.555$

7 0

3 years ago

Look at the data set below:

Elenna [48]

Median: Sort from least to greatest and find the # in the middle.
Sort: 54, 58, 58, 60, 62.
Number in the middle: 58, so the median is 58.
Mode: 58, because it appears most.
Range: Subtracting bigger number from smaller number.
Finding it: 62-54 = 8
If you want to find the mean, then here:
Mean: Solving average (adding all #s together and dividing by how many numbers are there) <span>58 + 54 + 62 + 58 + 60 = 292.
</span>Divide by 5 = 58.4
Hope that helps you. Good luck with it.
Follow if you want.

6 0

3 years ago

Read 2 more answers

Find the distance between the 2 points (6, - 4) and (2, - 7). Please show me how you found it.

Serga [27]

$\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ 6}}\quad ,&{{ -4}})\quad 
% (c,d)
&({{ 2}}\quad ,&{{ -7}})
\end{array}\qquad 
% distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
d=\sqrt{[2-6]^2+[-7-(-4)]^2}\implies d=\sqrt{(2-6)^2+(-7+4)^2}$